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November 1st, 2007, 04:16 PM
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| | fixed point mapping Trying to figure out these two questions, got the rest of them but can't remember my linear algebra for the life of me thanks!
a. make a continuous function (0,1] --> (0,1] without fixed points.
note: there is supposed to be some simple map but honestly I can't see it.
b. prove that the unit square [0,1]x[0,1] is homeomorphic to the parellelogram in RČ with vertices (3,2), (6,5), (4,4), and (7,7). Use a suitable map and an appropriate translation.
Thanks so much for the help appreciated. | 
November 1st, 2007, 06:40 PM
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| | Quote:
Originally Posted by ml692787 Trying to figure out these two questions, got the rest of them but can't remember my linear algebra for the life of me thanks!
a. make a continuous function (0,1] --> (0,1] without fixed points.
note: there is supposed to be some simple map but honestly I can't see it. | If it was [0,1] --> [0,1] it would be impossible by the the Brouwer fixed point theorem. However, here it is (0,1] hence take  . | 
November 1st, 2007, 07:06 PM
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| | Quote:
Originally Posted by ThePerfectHacker However, here it is (0,1] hence take  . | Surely is a fixed point for that mapping.
However, the following continuous function has no fixed point. | | The following users thank Plato for this useful post: | |  | 
November 1st, 2007, 08:09 PM
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| | thanks for the help, i'm trying to figure out how to do the second part, I forgot how to map a vector <2,1> to the unit vector <0,1>, and the vector <3,3> to <1,0>, thanks | | Thread Tools | | | | Display Modes | Linear Mode |
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