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November 4th, 2007, 10:20 AM
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| |  Higher Limits, L'Hospital's Rule
I can't figure out how to solve this:  = ?
Please help! |
November 4th, 2007, 10:55 AM
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You don't need to apply that Rule, just remember that 
And, ![\lim_{x \to \infty } \left( {1 + \frac{7}{x}} \right)^{x/5} = \lim_{x \to \infty } \left[ {\left( {1 + \frac{7}{x}} \right)^x } \right]^{1/5}](http://www.mathhelpforum.com/math-help/latex2/img/87fd5a268d2945985959cd1e68750213-1.gif "\lim_{x \to \infty } \left( {1 + \frac{7}{x}} \right)^{x/5} = \lim_{x \to \infty } \left[ {\left( {1 + \frac{7}{x}} \right)^x } \right]^{1/5}") | | The following users thank Krizalid for this useful post: | |  |
November 4th, 2007, 11:15 AM
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When I solve it, I get [1 + (Infinity / Infinity)]. I don't know what I'm doing wrong. | | Thread Tools | | | | Display Modes |  Linear Mode | 
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