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#1

$Old$ December 7th, 2007, 03:21 AM

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$Unhappy$ Confused by integration!

How to integrate the equation below? thx i am confused and my brain is filled with murky glue!

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(secx+tanx)dx (sorry the front symbol i dont know how to type in)

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#2

$Old$ December 7th, 2007, 05:10 AM

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Since you have a sum, integrate each term separately:

$\int {\sec x\,dx} = \int {\sec x \cdot \frac{{\sec x + \tan x}}{{\sec x + \tan x}}\,dx} .$

And for the another piece $\int {\tan x\,dx} = \int {\frac{{\sin x}}{{\cos x}}\,dx} = - \int {\frac{{(\cos x)'}}{{\cos x}}\,dx} .$

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$Old$ December 7th, 2007, 06:52 AM

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$\int sec(x)+tan(x)dx = \int \frac{1+sin(x)}{cos(x)}dx$

A good way to start with these is to put everything into sines and cosines.

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