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Old September 29th, 2008, 07:45 PM
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Exclamation Linear ODE problem

Hi, I am supposed to solve the linear ODE:

x(dy/dx) + 2y = (sin x) / x , y(2) = 1

Can anyone help me get started with this? I am at a loss for anything relevant.
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Old September 29th, 2008, 07:56 PM
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Hi, I am supposed to solve the linear ODE:

x(dy/dx) + 2y = (sin x) / x , y(2) = 1

Can anyone help me get started with this? I am at a loss for anything relevant.
do you mean y' = \frac {x^3 - 2y}x ?? ....hey! you changed the question!

so you have xy' +2y = \frac {\sin x}x

divide through by x, we get

y' + \frac 2xy = \frac {\sin x}{x^2}

now solve using the integrating factor method
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Old September 29th, 2008, 08:05 PM
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got it, it's even easier if you multiply through by x squared. (integrating factor is just x squared then!) thanks!
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Old September 29th, 2008, 08:25 PM
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got it, it's even easier if you multiply through by x squared. (integrating factor is just x squared then!) thanks!
right. i didn't know if you would catch that though, so i wanted to go by the book. sometimes you make such leaps in logic and students get lost and bewildered
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