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Old October 19th, 2008, 04:02 AM
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the solid lies between planes perpendicular to the x-axis at x=-1 and x= 1. The cross-sections perpendicular to the x-axis between the planes are squares whose bases run from the simicircle y^2=-(1-x2)to the semicircle y^2=(1-x^2)
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Old October 19th, 2008, 04:31 AM
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Originally Posted by auststudent View Post
the solid lies between planes perpendicular to the x-axis at x=-1 and x= 1. The cross-sections perpendicular to the x-axis between the planes are squares whose bases run from the simicircle y^2=-(1-x2)to the semicircle y^2=(1-x^2)
Do you have a QUESTION?

For example, are you asking what the volume of this solid is?

Imagine a very thin slice of this solid, perpendicular to the x-axis. It is, as you say, a square and let's say it's thickness is dx. According to you, one side of the square runs from -sqrt(1- x^2) to sqrt(1- x^2) and so is 2sqrt(1- x^2) long. What is the AREA of that square? The volume of that thin slice is that area times dx. Integrate that to find the volume. The limits of integration are, of course, the x values where the two semi-circles come together.
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Old October 19th, 2008, 05:11 AM
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Originally Posted by auststudent View Post
the solid lies between planes perpendicular to the x-axis at x=-1 and x= 1. The cross-sections perpendicular to the x-axis between the planes are squares whose bases run from the simicircle y^2=-(1-x2)to the semicircle y^2=(1-x^2)
i wana the volume and i cannot get it
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