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Old October 19th, 2008, 11:12 AM
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Default dynamical system

hey, can anybody help?
i have a 1 dimensional dynamical system in which x is greater than 0
x(with a dot on top)=f(x)=1-(5x^2)+(4x^4)
how to i solve f(x*)=0 and find its fixed points?
thanks
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Old October 19th, 2008, 11:27 AM
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You want to solve
0 = 4\cdot x^4 - 5\cdot x^2+1
Let u = x^2
Then 0 = 4\cdot u^2 - 5\cdot u+1
And you solve the quadratic
u = \frac {5 \pm  \sqrt{25-9}}{8}
x = \pm\sqrt {u} = \pm 1 or \pm \frac{1}{2}

Last edited by vincisonfire; October 19th, 2008 at 11:38 AM.
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