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  #1  
Old December 3rd, 2008, 03:58 PM
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Default riemann integrable

Suppose that f is continuous on [a,b], that f(x)≥0 for all x within [a,b] and that . Prove that f(x)=0 for all x within [a,b]. Also, show that the continuity hypothesis cannot be dropped.
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Old December 3rd, 2008, 04:24 PM
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Here is a hint.
If \left( {\exists c \in [a,b]} \right)\left[ {f(c) > 0} \right] then \left( {\exists [d,e] \subseteq [a,b]} \right)\left( {\forall z \in [d,e]} \right)\left[ {f(z) > \frac{{f(c)}}{2}} \right].
Ask yourself what is the minimum value of \int_d^e {f(x)dx}.

Now drop continuity: f(x) = \left\{ {\begin{array}{rl}
   {1/n} & {x = a + 1/n}  \\
   0 & {else}  \\

 \end{array} } \right..
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Old December 4th, 2008, 09:29 AM
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Quote:
Originally Posted by Plato View Post
Here is a hint.
If \left( {\exists c \in [a,b]} \right)\left[ {f(c) > 0} \right] then \left( {\exists [d,e] \subseteq [a,b]} \right)\left( {\forall z \in [d,e]} \right)\left[ {f(z) > \frac{{f(c)}}{2}} \right].
Ask yourself what is the minimum value of \int_d^e {f(x)dx}.

Now drop continuity: f(x) = \left\{ {\begin{array}{rl}   {1/n} & {x = a + 1/n}  \\   0 & {else}  \\ \end{array} } \right..
Tired messing around with your hint but could not get anywehre.
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