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January 22nd, 2009, 05:04 PM
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| |  Midpoint rule integration
Use the Midpoint Rule to approximate the integral
the 3 is on the top, and the -6 is on the bottom, and n=3.
\int_{-6}^{3}(6 x - 3 x^2)dx
Can anyone solve this I can't figure it out. |
January 22nd, 2009, 05:54 PM
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January 22nd, 2009, 06:07 PM
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Hmm, that still doesn't make sense to me =/, what would be the numerical answer exactly? |
January 22nd, 2009, 06:25 PM
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Quote:
Originally Posted by serix  Hmm, that still doesn't make sense to me =/, what would be the numerical answer exactly? | use your calculator. | | Thread Tools | | | | Display Modes |  Linear Mode | 
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![\int_{-6}^3 f(x) \, dx \approx \left[\frac{3 - (-6)}{3}\right] \cdot \left[f(-4.5) + f(-1.5) + f(1.5)\right]](http://www.mathhelpforum.com/math-help/latex2/img/f3096ce28f78897d128c3fef4e1a7c55-1.gif "\int_{-6}^3 f(x) \, dx \approx \left[\frac{3 - (-6)}{3}\right] \cdot \left[f(-4.5) + f(-1.5) + f(1.5)\right]")
