2nd order differential equation

nirvanakris · #1 $Old$ November 1st, 2009, 05:56 AM

please help me...its for my project!!!
thanks in advance
solve for U(x,t), note that U=U(x,t)
Delta(Ut) + 0.1 Delta(Ux) = 0.2 Delta( Uxx)
.
.
.
.
.
Answer: U(x,t) = Exp (1.17712434…x – 0.09t), Exp--> exponential

HallsofIvy · #2 $Old$ November 1st, 2009, 06:44 AM

Quote:

Originally Posted by nirvanakris $View Post$

please help me...its for my project!!!
thanks in advance
solve for U(x,t), note that U=U(x,t)
Delta(Ut) + 0.1 Delta(Ux) = 0.2 Delta( Uxx)

"Delta" is not standard notation. better would be just "U_t+ 0.1U_x= .2U_xx
.

Quote:

.
.
.
.
Answer: U(x,t) = Exp (1.17712434…x – 0.09t), Exp--> exponential

If you give no initial or boundary conditions, it is impossible to get that! Tell us what the problem really says.

nirvanakris · #3 $Old$ November 2nd, 2009, 01:31 AM

Quote:

Originally Posted by HallsofIvy $View Post$

"Delta" is not standard notation. better would be just "U_t+ 0.1U_x= .2U_xx
.

If you give no initial or boundary conditions, it is impossible to get that! Tell us what the problem really says.

sory, ive forgot the boudaries...in fact the boudaries are given as :
o<=x<=1, t>=0 thanks in advance!!

nirvanakris · #4 $Old$ November 2nd, 2009, 01:33 AM

Quote:

Originally Posted by HallsofIvy $View Post$

"Delta" is not standard notation. better would be just "U_t+ 0.1U_x= .2U_xx
.

If you give no initial or boundary conditions, it is impossible to get that! Tell us what the problem really says.

sory, ive forgot the boudaries...
so the problem is actually U_t+ 0.1U_x= .02U_xx and the boudaries are given as :
o<=x<=1, t>=0 thanks in advance!!