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September 14th, 2008, 06:04 PM
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Use the definition of the derivative to find f' (x).
f (x)= 
The answer I got is 
Can someone tell me if this is right? If it isn't, I will post my work to see where I went wrong. |
September 14th, 2008, 06:10 PM
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Quote:
Originally Posted by yeloc  Use the definition of the derivative to find f' (x).
f (x)=
The answer I got is
Can someone tell me if this is right? If it isn't, I will post my work to see where I went wrong. | it is wrong
and this is not a differential equation 
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September 14th, 2008, 06:15 PM
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Quote:
Originally Posted by Jhevon it is wrong
and this is not a differential equation | How is it not when you have to use a differential equation to solve it? |
September 14th, 2008, 06:17 PM
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Quote:
Originally Posted by yeloc Use the definition of the derivative to find f' (x).
f (x)=
The answer I got is 
Can someone tell me if this is right? If it isn't, I will post my work to see where I went wrong. | If it was  , then you'd be correct!
What's the derivative of  ?
Recall that 
--Chris
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Last edited by Chris L T521; September 14th, 2008 at 06:25 PM.
Reason: ooppss... XD
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September 14th, 2008, 06:26 PM
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Quote:
Originally Posted by yeloc How is it not when you have to use a differential equation to solve it? | you are doing basic calculus. "differential equations" refers to something else. see here
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September 14th, 2008, 06:27 PM
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Originally Posted by Chris L T521 If it was , then you'd be correct! | technically yes, technically no. it would depend on whether we are considering negative x's or positive or both. remember, 
it is better not to simplify in this case, so there is no ambiguities. just apply the chain rule, as you so rightly directed, and call it a day
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September 14th, 2008, 06:39 PM
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After I substituted  in for x, and used the definition of the derivative of a function to set the rest of the problem up, how would I get  out of the denominator?
I used the conjugate method, then I got a common denominator. I just simplified from there on out. Is this not right? |
September 14th, 2008, 06:44 PM
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Quote:
Originally Posted by yeloc After I substituted in for x, and used the definition of the derivative of a function to set the rest of the problem up, how would I get out of the denominator?
I used the conjugate method, then I got a common denominator. I just simplified from there on out. Is this not right? | you have the right idea. whether or not you did it right, i don't know
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