In general if dy/dx = f(y)
Then the steady state solutions are the zeroes of f(y)
Let a =alpha
For dN/dt = rN(1-aN) - h
Steady states are found when rN(1-aN) - h = 0
Expanding -arN^2 + rN - h = 0
Use the good ol' quadratic formula
N = 1/2a
+ sqrt(r^2 - 4arh)/2ar
this will clean up to 1/2a
+ sqrt(1-4ah/r)/2a
or N = [1
+ sqrt(1-4ah/r)]/2a
since r > 4ah the solutions are real
By considering a graph of dN/dt vs N you should be able to determine N1 unstable and N2 stable
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