Math Help Forum

Math Help Forum Feed Site Feed

Go Back   Math Help Forum > University Math Help > Discrete Mathematics, Set Theory and Logic
Reply
 
Thread Tools Display Modes
  #1  
Old November 2nd, 2009, 04:24 PM
Deadstar's Avatar
Senior Member
 
Join Date: Oct 2007
Posts: 333
Country:
Thanks: 77
Thanked 67 Times in 61 Posts
Deadstar will become famous soon enough
Default Well ordered set

Suppose (A,\leq) is a well-ordered set. Let B = \mathbb{R}^A. Find an explicit linear order on B.

So I have to prove reflexivity, antisymmetry, transitivity and that B is linear. Thing is I cant really get my head around what B = \mathbb{R}^A actually is... Set of functions from A to \mathbb{R}. But A is well ordered... So how does that change things?

Does this involve creating an in/bijection between B and some well ordered set?
Reply With Quote
Advertisement
 
  #2  
Old November 3rd, 2009, 03:36 AM
Newbie
 
Join Date: Oct 2009
Posts: 14
Thanks: 7
Thanked 0 Times in 0 Posts
whatisthisfor is on a distinguished road
Default

clic-clac explained how to form the linear order pretty well for me:

Finding a linear order on a set

proving the rest is a bit easier.

Now, know anything about question 4? Ordinal Arithmetic
Reply With Quote
Reply

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off
Forum Jump


All times are GMT -7. The time now is 04:37 AM.


Powered by vBulletin® Version 3.7.3
Copyright ©2000 - 2010, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.2.0 ©2008, Crawlability, Inc.
©2005 - 2009 Math Help Forum


Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.