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November 6th, 2009, 02:16 PM
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| | Counting A candy factory has an endless supply of red, orange, yellow, green, blue, and violet jelly beans. The factory packages the jelly beans into jars of 84 jelly beans each. As a marketing gimmick, the factory guarantees that no two jars have exactly the same number of red, orange, yellow, green, blue, and violet jelly beans. What is the maximum number of jars the factory can produce? | 
November 6th, 2009, 02:26 PM
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Originally Posted by essedra A candy factory has an endless supply of red, orange, yellow, green, blue, and violet jelly beans. The factory packages the jelly beans into jars of 84 jelly beans each. As a marketing gimmick, the factory guarantees that no two jars have exactly the same number of red, orange, yellow, green, blue, and violet jelly beans. What is the maximum number of jars the factory can produce? | How many non-negative integral solutions are there to this equation are there: | 
November 6th, 2009, 02:31 PM
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Originally Posted by Plato How many non-negative integral solutions are there to this equation are there:  | I didn't get what you mean... | 
November 6th, 2009, 02:33 PM
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| | I tried to solve it like this:
6x6x6x6x6x6x6x6x6x6x6x6x6x6x6........ (84 times) =
6^84 = 2 + 65 zeros
which is same as
2x10^65
but the answer was incorrect... | 
November 6th, 2009, 02:42 PM
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Originally Posted by essedra I didn't get what you mean... | Somewhere in you text-material there must be a section of making multi-selections.
How many ways to put N identical objects into K different cells:  .
So when I asked about many solutions to  ,
that is equivalent putting 84 identical ones into six different colors.
Each solution is one way the candy factory can package the 84 jelly beans. | 
November 6th, 2009, 02:53 PM
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| | I still couldn't solve the problem, because i'm confused about the "k" you're talking about...are order and repetition important? | 
November 6th, 2009, 03:02 PM
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| | I would be really grateful if you could show me the way to solve this problem... | 
November 6th, 2009, 03:08 PM
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Originally Posted by essedra I still couldn't solve the problem, because i'm confused about the "k" you're talking about...are order and repetition important? | Let me give you an example.
Suppose that an ice cream shop has 21 flavors.
It runs a special offer of a plate of 4 scoops of any combinations.
How many different offerings are there?
Answer:
That is the number of ways to put 4 identical objects (scoops) into 21 (flavors) different cells.
Note that the 4 can be all different, all the same, or say two of one and two different. | 
November 6th, 2009, 03:21 PM
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| | so I applied what you said...
89!/(6!*84! ) = 6917940,3333333333333333333333333
but the result was incorrect... | 
November 6th, 2009, 03:26 PM
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Originally Posted by essedra so I applied what you said...
89!/(6!*84! ) = 6917940,3333333333333333333333333
but the result was incorrect... | I don't think that you have caculated that correctly. | | The following users thank Plato for this useful post: | |  | | Thread Tools | | | | Display Modes | Linear Mode |
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