Simplifying Indices - Math Help Forum

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#1

$Old$ 11-14-2008, 06:43 PM

Markus123 $Markus123 is offline$

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$Default$ Simplifying Indices

Hi,

Could somebody please tell me where I'm going wrong, or if it's the book that's wrong on this (easy) question:

$\frac{2^6}{8^{2\frac{1}{2}}*2^{-\frac{1}{2}}}$

I get:

$\frac{2^6}{(2^3)^{2\frac{1}{2}}*2^{-\frac{1}{2}}}$

$= \frac{2^6}{2^{7\frac{1}{2}}*2^{-\frac{1}{2}}}$

$= \frac{2^6}{2^7}$

$= 2^{-1}$

$= \frac{1}{2}$

The book however has the answer as:

$2^\frac{39}{4}$

I'm pretty sure I'm right because multiplying it out gives 0.5, but I tried it in an online solver and they come out with the same answer as the book.

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#2

$Old$ 11-15-2008, 02:48 AM

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Hello,

Unless you didn't copy the text well, I don't see any mistake in your working

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#3

$Old$ 11-15-2008, 03:41 AM

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Quote:

Originally Posted by Moo $View Post$

Hello,

Unless you didn't copy the text well, I don't see any mistake in your working

Skype Surprised

What about this

$(2^3)^2 = 2^7$
?

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