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		<title>Math Help Forum - Trigonometry</title>
		<link>http://www.mathhelpforum.com/math-help/</link>
		<description>Graphing trig expressions, identities, angles, applied questions</description>
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			<title>Math Help Forum - Trigonometry</title>
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		<item>
			<title>Trigonometry Proof</title>
			<link>http://www.mathhelpforum.com/math-help/f14/trigonometry-proof-155601.html</link>
			<pubDate>Wed, 08 Sep 2010 23:33:47 GMT</pubDate>
			<description>Can someone please prove this equation: 
  
_  Cos x   _ + _   Cos x  _  = 2Sec x 
1 - Sin x     1 + Sin x</description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->Can someone please prove this equation:<br />
 <br />
<u>  Cos x   </u> + <u>   Cos x  </u>  <font size="2">= 2Sec x</font><br />
1 - Sin x     1 + Sin x<!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>GAVREED2</dc:creator>
			<guid isPermaLink="true">http://www.mathhelpforum.com/math-help/f14/trigonometry-proof-155601.html</guid>
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			<title>Rotation of a square on a plane</title>
			<link>http://www.mathhelpforum.com/math-help/f14/rotation-square-plane-155548.html</link>
			<pubDate>Wed, 08 Sep 2010 12:25:23 GMT</pubDate>
			<description>Hi All, 
 
I hope you can help (and I hope this is the right forum for this subject) 
 
I have a resizeable plane (say 300 x 300 in size) 
On this plane I have a square (say 290 x 290 in size) 
 
When i rotate this square on this plane by say 25 degrees around the squares center parts of the square...</description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->Hi All,<br />
<br />
I hope you can help (and I hope this is the right forum for this subject)<br />
<br />
I have a resizeable plane (say 300 x 300 in size)<br />
On this plane I have a square (say 290 x 290 in size)<br />
<br />
When i rotate this square on this plane by say 25 degrees around the squares center parts of the square are no longer visible on the existing plane.<br />
<br />
My goal is to have the plane resize based on the new square but all I have available is the original dimensions of the plane, the original dimensions of the square and the angle it's being rotated by in my problem i do have access to various trigonometric functions such as cos and sin, I also know the center of the original square.<br />
<br />
basically i'm looking for an equation which would take the angle and dimensions of the original square and plane and produce the new correct dimensions for the plane so that it engulfs the new square<br />
<br />
Please anyone that could help I am desperate for help<br />
<br />
kind regards<br />
James<!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>hellzone</dc:creator>
			<guid isPermaLink="true">http://www.mathhelpforum.com/math-help/f14/rotation-square-plane-155548.html</guid>
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		<item>
			<title>Find SEC</title>
			<link>http://www.mathhelpforum.com/math-help/f14/find-sec-155524.html</link>
			<pubDate>Wed, 08 Sep 2010 05:29:36 GMT</pubDate>
			<description>Find SEC Can someone tell me if this is correct 
 
Given that sec(theta) = 1.75. find (theta) in degrees  
  
Image: http://www.mathhelpforum.com/math-help/vlatex/pics/63_2dc4699cc3349d7ad82484c603d890c8.png</description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->Find SEC <blockquote>Can someone tell me if this is correct<br />
<br />
Given that sec(theta) = 1.75. find (theta) in degrees <br />
 <br />
<img src="http://www.mathhelpforum.com/math-help/vlatex/pics/63_2dc4699cc3349d7ad82484c603d890c8.png" border="0" alt="" /><br />
<br />
</blockquote><!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>GAVREED2</dc:creator>
			<guid isPermaLink="true">http://www.mathhelpforum.com/math-help/f14/find-sec-155524.html</guid>
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			<title>sin(A+B) and cos rule</title>
			<link>http://www.mathhelpforum.com/math-help/f14/sin-b-cos-rule-155519.html</link>
			<pubDate>Wed, 08 Sep 2010 04:15:54 GMT</pubDate>
			<description>Solving using sin(A+B) and cos rule Can someone show each od the steps and answer for this question. It will give something to work off for the rest of them. Very much appreciated 
 
*1) Using the identities for sin(A+B) and cos^2(theta)+sin^2(theta)=1.* 
 
*Find sine 65 degrees, given that sin...</description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->Solving using sin(A+B) and cos rule <blockquote>Can someone show each od the steps and answer for this question. It will give something to work off for the rest of them. Very much appreciated<br />
<br />
<b><i>1) Using the identities for sin(A+B) and cos^2(theta)+sin^2(theta)=1.</i></b><br />
<br />
<b><i>Find sine 65 degrees, given that sin 40(degrees)=0.643 and sin 25(degrees)=0.423?</i></b><br />
</blockquote><!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>GAVREED2</dc:creator>
			<guid isPermaLink="true">http://www.mathhelpforum.com/math-help/f14/sin-b-cos-rule-155519.html</guid>
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			<title>Proof that this equation is valid (have tried to solve myself many times..)</title>
			<link>http://www.mathhelpforum.com/math-help/f14/proof-equation-valid-have-tried-solve-myself-many-times-155475.html</link>
			<pubDate>Tue, 07 Sep 2010 17:06:32 GMT</pubDate>
			<description><![CDATA[First of all, I must say that I really like this board. Mathematics is my favorite subject in school and I find many things I read here very informative.. 
 
My question: 
I've been trying to proof the following equation to be true for 2 days now, but I just don't seem to get it right. Could you...]]></description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->First of all, I must say that I really like this board. Mathematics is my favorite subject in school and I find many things I read here very informative..<br />
<br />
My question:<br />
I've been trying to proof the following equation to be true for 2 days now, but I just don't seem to get it right. Could you guys help me with it? (You don't even have to show the full way how you did it, some info on how I should get started would be perfect too).<br />
<br />
<img src="http://img819.imageshack.us/img819/7428/equation.jpg" border="0" alt="" /><!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>DaFlyinFin</dc:creator>
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			<title>Solution of Oblique Triangles Help</title>
			<link>http://www.mathhelpforum.com/math-help/f14/solution-oblique-triangles-help-155467.html</link>
			<pubDate>Tue, 07 Sep 2010 14:44:11 GMT</pubDate>
			<description><![CDATA[How to solve for this problem? 
 
> One diagonal of a parallelogram is 16.5. It makes angle of 36°10' and 14°30' respectively with the sides. Find the sides.]]></description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->How to solve for this problem?<br />
<br />
&gt; One diagonal of a parallelogram is 16.5. It makes angle of 36°10' and 14°30' respectively with the sides. Find the sides.<!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>khms</dc:creator>
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			<title>Using Trigonometric Identity</title>
			<link>http://www.mathhelpforum.com/math-help/f14/using-trigonometric-identity-155431.html</link>
			<pubDate>Tue, 07 Sep 2010 06:08:19 GMT</pubDate>
			<description><![CDATA[a) Find the exact value of sin 135 by using sin (180 &#8211; 45) 
 
b)  Find the exact value of sin 225 by using sin (270 &#8211; 45) 
b)  Use the value of sin 225 found in b to find sin (&#8211;15) by using sin (225  &#8211; 240)]]></description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->a) Find the exact value of sin 135 by using sin (180 &#8211; 45)<br />
<br />
b)  Find the exact value of sin 225 by using sin (270 &#8211; 45)<br />
b)  Use the value of sin 225 found in b to find sin (&#8211;15) by using sin (225  &#8211; 240)<!-- google_ad_section_end --></div>

 ]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>soni</dc:creator>
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			<title>Sin and Cos</title>
			<link>http://www.mathhelpforum.com/math-help/f14/sin-cos-155404.html</link>
			<pubDate>Tue, 07 Sep 2010 01:24:45 GMT</pubDate>
			<description><![CDATA[How do I solve this? I have been working on this same problem for about an hour and can't come up with anything. I have to find the value of A, w, and b. 
  
2sin(12x + 1) + 3sin(12x + 3) = A sin(wx + b) 
  
Any help (with steps included) would be GREATLY appreciated! Thanks!]]></description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->How do I solve this? I have been working on this same problem for about an hour and can't come up with anything. I have to find the value of A, w, and b.<br />
 <br />
2sin(12x + 1) + 3sin(12x + 3) = A sin(wx + b)<br />
 <br />
Any help (with steps included) would be GREATLY appreciated! Thanks!<!-- google_ad_section_end --></div>

 ]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>aeagan2</dc:creator>
			<guid isPermaLink="true">http://www.mathhelpforum.com/math-help/f14/sin-cos-155404.html</guid>
		</item>
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			<title>Trigonometry and Surds</title>
			<link>http://www.mathhelpforum.com/math-help/f14/trigonometry-surds-155371.html</link>
			<pubDate>Mon, 06 Sep 2010 19:12:48 GMT</pubDate>
			<description><![CDATA[Hello there, 
 
I have a problem solving question which has been frustrating me: 
 
A triangle has sides of lengths &#8730;6, 3&#8730;2 and 3&#8730;3 units. 
 
Is the triangle right angled? You must give a reason for your answer. 
 
Any help would be greatly appreciated, thank you.]]></description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->Hello there,<br />
<br />
I have a problem solving question which has been frustrating me:<br />
<br />
A triangle has sides of lengths &#8730;6, 3&#8730;2 and 3&#8730;3 units.<br />
<br />
Is the triangle right angled? You must give a reason for your answer.<br />
<br />
Any help would be greatly appreciated, thank you.<br />
<br />
OJW<!-- google_ad_section_end --></div>

 ]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>OJW</dc:creator>
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			<title><![CDATA[What's the difference between these two trig identity problems?]]></title>
			<link>http://www.mathhelpforum.com/math-help/f14/whats-difference-between-these-two-trig-identity-problems-155336.html</link>
			<pubDate>Mon, 06 Sep 2010 12:00:17 GMT</pubDate>
			<description>1) 2 \tan x=3 \sin x 
2 \frac{\sin x}{\cos x}=3 \sin x \rightarrow 2 \sin x = 3 \sin x \cos x \rightarrow \sin x(2 - 3 \cos x)=0 
a) \sin x = 0 \rightarrow x =180n 
b) \cos x = \frac{2}{3} \rightarrow x =48.19 + *360n* 
 
2) 2 \sin 2x \cos ^2 x = \sin 2x 
\sin 2x(2 \cos ^2 x -1) =0 \rightarrow 
a)...</description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->1) <img class="pod_vlatex_inline" src="vlatex/pics/17_a4cdad184838d4b80b7ed4f3fd65eef1.png" alt="" title="Double click to see source code" style="vertical-align: 0.00pt;" onDblClick='vlatex_dblclick(this, "2 &amp;#92;tan x=3 &amp;#92;sin x")' /><br />
<img class="pod_vlatex_inline" src="vlatex/pics/44_c236960a1329a5d21c8b11dbcc37c1a4.png" alt="" title="Double click to see source code" style="vertical-align: -4.15pt;" onDblClick='vlatex_dblclick(this, "2 &amp;#92;frac{&amp;#92;sin x}{&amp;#92;cos x}=3 &amp;#92;sin x &amp;#92;rightarrow")' /> <img class="pod_vlatex_inline" src="vlatex/pics/38_9303f2b18d4b8b220fa1394873135969.png" alt="" title="Double click to see source code" style="vertical-align: 0.00pt;" onDblClick='vlatex_dblclick(this, "2 &amp;#92;sin x = 3 &amp;#92;sin x &amp;#92;cos x &amp;#92;rightarrow")' /> <img class="pod_vlatex_inline" src="vlatex/pics/22_1b33af8e351019c014bc79f6a88f5530.png" alt="" title="Double click to see source code" style="vertical-align: -3.01pt;" onDblClick='vlatex_dblclick(this, "&amp;#92;sin x(2 - 3 &amp;#92;cos x)=0")' /><br />
a) <img class="pod_vlatex_inline" src="vlatex/pics/30_6e0ffe2196be01b27fb2dc08a4f42456.png" alt="" title="Double click to see source code" style="vertical-align: 0.00pt;" onDblClick='vlatex_dblclick(this, "&amp;#92;sin x = 0 &amp;#92;rightarrow x =180n")' /><br />
b) <img class="pod_vlatex_inline" src="vlatex/pics/36_6c61ce97a28d0b8fda515881345578a3.png" alt="" title="Double click to see source code" style="vertical-align: -4.15pt;" onDblClick='vlatex_dblclick(this, "&amp;#92;cos x = &amp;#92;frac{2}{3} &amp;#92;rightarrow x =")' />48.19 + <b>360n</b><br />
<br />
2) <img class="pod_vlatex_inline" src="vlatex/pics/29_f3e7c83833898552d7b964d30ae74d4d.png" alt="" title="Double click to see source code" style="vertical-align: 0.00pt;" onDblClick='vlatex_dblclick(this, "2 &amp;#92;sin 2x &amp;#92;cos ^2 x = &amp;#92;sin 2x")' /><br />
<img class="pod_vlatex_inline" src="vlatex/pics/38_8f245becab197d60f109768750ffc3d2.png" alt="" title="Double click to see source code" style="vertical-align: -3.01pt;" onDblClick='vlatex_dblclick(this, "&amp;#92;sin 2x(2 &amp;#92;cos ^2 x -1) =0 &amp;#92;rightarrow")' /><br />
a) <img class="pod_vlatex_inline" src="vlatex/pics/49_a787800574f458dfa40c6bb0e2a5037c.png" alt="" title="Double click to see source code" style="vertical-align: 0.00pt;" onDblClick='vlatex_dblclick(this, "&amp;#92;sin 2x=0 &amp;#92;rightarrow 2x=180n &amp;#92;rightarrow x = 90n")' /><br />
b) <img class="pod_vlatex_inline" src="vlatex/pics/68_7fdfc4834f6de1e37a5cc77d07927269.png" alt="" title="Double click to see source code" style="vertical-align: -7.41pt;" onDblClick='vlatex_dblclick(this, "&amp;#92;cos ^2 x = &amp;#92;frac{1}{2} &amp;#92;rightarrow &amp;#92;cos x = &amp;#92;pm &amp;#92;sqrt{&amp;#92;frac{1}{2} }")' /><br />
<img class="pod_vlatex_inline" src="vlatex/pics/7_aa41c3ee157e0b0666c51d2c9f5c99d9.png" alt="" title="Double click to see source code" style="vertical-align: -1.00pt;" onDblClick='vlatex_dblclick(this, "x = &amp;#92;pm")' /> 45 + <b>360n</b><br />
<br />
of course the answer to number 2 is <img class="pod_vlatex_inline" src="vlatex/pics/3_cf93b622e4dc3cc11a3fe5813255d42d.png" alt="" title="Double click to see source code" style="vertical-align: -1.00pt;" onDblClick='vlatex_dblclick(this, "&amp;#92;pm")' /> 45 + <b>180n</b><br />
but the answer to number 1 is 48.19 + <b>360n</b>! So what's the difference between the two? They are both cosine functions. I just thought always add 360 degrees because that's when the angle repeats itself.<br />
<br />
(*fixed the bold...)<!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>jayshizwiz</dc:creator>
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			<title>bearing</title>
			<link>http://www.mathhelpforum.com/math-help/f14/bearing-155335.html</link>
			<pubDate>Mon, 06 Sep 2010 11:31:21 GMT</pubDate>
			<description><![CDATA[[ATTACH=CONFIG]18840[/ATTACH] 
  
kindly answer the bearing... i got the angle at forest island but i dont know how to get the bearing in from forst island to home port.. 
  
the bearing should be South East, but what degrees]]></description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start --><a href="http://www.mathhelpforum.com/math-help/attachments/f14/18840-bearing-bearing.png"  title="Name:  
Views: 
Size:  ">Attachment 18840</a><br />
 <br />
kindly answer the bearing... i got the angle at forest island but i dont know how to get the bearing in from forst island to home port..<br />
 <br />
the bearing should be South East, but what degrees<!-- google_ad_section_end --></div>


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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>aeroflix</dc:creator>
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			<title>sin(x), sin(2x), sin(1/2)....what is the period?</title>
			<link>http://www.mathhelpforum.com/math-help/f14/sin-x-sin-2x-sin-1-2-what-period-155316.html</link>
			<pubDate>Mon, 06 Sep 2010 07:23:38 GMT</pubDate>
			<description>sin(x), sin(2x), sin(1/2)....what are the periods? 
 
Pls explain to me the concepts involved so I can remember more clearly. 
 
Thanks.</description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->sin(x), sin(2x), sin(1/2)....what are the periods?<br />
<br />
Pls explain to me the concepts involved so I can remember more clearly.<br />
<br />
Thanks.<!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>stupidguy</dc:creator>
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			<title>Help with simple goniometrics</title>
			<link>http://www.mathhelpforum.com/math-help/f14/help-simple-goniometrics-155228.html</link>
			<pubDate>Sun, 05 Sep 2010 09:05:59 GMT</pubDate>
			<description><![CDATA[Hi heres my problem - 
 
tan(&#945;/2) = (l/2)/d, hence &#945; = 2*atan(l/2d) 
 
 
with this formula I can calculate the horizontal field-of-view of my camera.  
 
 
 
I found it at this site -  Determining the viewing angle of your camera (http://www.dr-lex.be/info-stuff/viewangle.html)]]></description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->Hi heres my problem -<br />
<br />
tan(&#945;/2) = (<i>l</i>/2)/<i>d</i>, hence<blockquote> &#945; = 2*atan(<i>l</i>/2<i>d</i>)<br />
<br />
<br />
with this formula I can calculate the horizontal field-of-view of my camera. <br />
<br />
<br />
<br />
I found it at this site -  <a href="http://www.dr-lex.be/info-stuff/viewangle.html" target="_blank">Determining the viewing angle of your camera</a> <br />
<br />
<br />
Only I havent a scientific calculator or the where with all to solve this! <br />
<br />
<br />
<br />
I need to find a - the angle of view.<br />
I know that l is the width - 2290mm<br />
and I know that d is the distance - 5000mm<br />
<br />
<br />
Any help from your forum members would be great! please save me any more days trawling endless websites trying to make sense of this!<br />
<br />
<br />
Thanks<br />
JayT<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
<br />
 </blockquote><!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>mrtea</dc:creator>
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			<title>trig identities  help needed</title>
			<link>http://www.mathhelpforum.com/math-help/f14/trig-identities-help-needed-155210.html</link>
			<pubDate>Sun, 05 Sep 2010 02:11:12 GMT</pubDate>
			<description>so i have my end of prelims coming up and doing a revision test. this question came up 
 
 prove (sec^2x - 1)cos^2x = sin^2x  
Now i thought that you would do the question like this: 
 
LHS = (sec^2x-1)cos^2x = (Tan^2x)cos^2x 
                                         = \frac{\sin^2x}{cos^2x} cos^2x...</description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->so i have my end of prelims coming up and doing a revision test. this question came up<br />
<br />
<img class="pod_vlatex_inline" src="vlatex/pics/35_b1f2acaf5d0b0e6dff1d5a2c4129ec70.png" alt="" title="Double click to see source code" style="vertical-align: -3.01pt;" onDblClick='vlatex_dblclick(this, " prove (sec^2x - 1)cos^2x = sin^2x ")' /><br />
Now i thought that you would do the question like this:<br />
<br />
<img class="pod_vlatex_inline" src="vlatex/pics/166_85a6469584d1c85ee572d9e16ba4f579.png" alt="" title="Double click to see source code" style="vertical-align: -4.15pt;" onDblClick='vlatex_dblclick(this, "LHS = (sec^2x-1)cos^2x = (Tan^2x)cos^2x&lt;br /&gt;                                          = &amp;#92;frac{&amp;#92;sin^2x}{cos^2x} cos^2x&lt;br /&gt;                                          =sin^2x&lt;br /&gt;  ")' /><br />
<br />
but it gave a different soln. am i wrong?<!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>link0099</dc:creator>
			<guid isPermaLink="true">http://www.mathhelpforum.com/math-help/f14/trig-identities-help-needed-155210.html</guid>
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		<item>
			<title><![CDATA[[SOLVED] some more trig identities]]></title>
			<link>http://www.mathhelpforum.com/math-help/f14/some-more-trig-identities-155204.html</link>
			<pubDate>Sat, 04 Sep 2010 22:57:35 GMT</pubDate>
			<description><![CDATA[hi. I think i'm getting the hang of these problems but I still need some assistance: 
 
1) cos^2x+sinx=1 
cos^2x+sinx=cos^2x+sin^2x \rightarrow sinx - sin^2x=0 \rightarrow sinx(1-sinx)=0 
sinx_1 = 0 \rightarrow x_1=180n 
1-sinx_2=0 \rightarrow sinx_2=1 \rightarrow x_2=90+360n 
 
2) 4sin^3x-sinx=0...]]></description>
			<content:encoded><![CDATA[<div><!-- google_ad_section_start -->hi. I think i'm getting the hang of these problems but I still need some assistance:<br />
<br />
1) <img class="pod_vlatex_inline" src="vlatex/pics/13_58f00c22ceb184c663e1cd3e7ff23a7e.png" alt="" title="Double click to see source code" style="vertical-align: -0.92pt;" onDblClick='vlatex_dblclick(this, "cos^2x+sinx=1")' /><br />
<img class="pod_vlatex_inline" src="vlatex/pics/80_8c616527b691fbbeda390655056194b2.png" alt="" title="Double click to see source code" style="vertical-align: -3.01pt;" onDblClick='vlatex_dblclick(this, "cos^2x+sinx=cos^2x+sin^2x &amp;#92;rightarrow sinx - sin^2x=0 &amp;#92;rightarrow sinx(1-sinx)=0")' /><br />
<img class="pod_vlatex_inline" src="vlatex/pics/31_0ad1da1ef0ad72371eee72090db2f2de.png" alt="" title="Double click to see source code" style="vertical-align: -1.81pt;" onDblClick='vlatex_dblclick(this, "sinx_1 = 0 &amp;#92;rightarrow x_1=180n")' /><br />
<img class="pod_vlatex_inline" src="vlatex/pics/55_db51377a9a1303d9c026ec13161d261d.png" alt="" title="Double click to see source code" style="vertical-align: -1.81pt;" onDblClick='vlatex_dblclick(this, "1-sinx_2=0 &amp;#92;rightarrow sinx_2=1 &amp;#92;rightarrow x_2=90+360n")' /><br />
<br />
2) <img class="pod_vlatex_inline" src="vlatex/pics/14_08f50808e3488072978087d3e7f870f6.png" alt="" title="Double click to see source code" style="vertical-align: -1.00pt;" onDblClick='vlatex_dblclick(this, "4sin^3x-sinx=0")' /><br />
<img class="pod_vlatex_inline" src="vlatex/pics/17_b659d906a1877856a8b3490a885f47a0.png" alt="" title="Double click to see source code" style="vertical-align: -3.01pt;" onDblClick='vlatex_dblclick(this, "sinx(4sin^2x-1)=0")' /><br />
<img class="pod_vlatex_inline" src="vlatex/pics/13_294a5b31755ebe0d5b9edece103e09b5.png" alt="" title="Double click to see source code" style="vertical-align: -1.81pt;" onDblClick='vlatex_dblclick(this, "sinx_1 = 180n")' /><br />
<img class="pod_vlatex_inline" src="vlatex/pics/85_98541cb240e8e1f2d9b768c19efc1edd.png" alt="" title="Double click to see source code" style="vertical-align: -3.01pt;" onDblClick='vlatex_dblclick(this, "4sin^2x_2-1=0 &amp;#92;rightarrow sin^2x=1/4 &amp;#92;rightarrow sinx=1/2 &amp;#92;rightarrow x_2 = +-30+180n")' /><br />
<br />
3) <img class="pod_vlatex_inline" src="vlatex/pics/17_82ace1a9de3e1c4aa5834d23ef7c0906.png" alt="" title="Double click to see source code" style="vertical-align: -1.00pt;" onDblClick='vlatex_dblclick(this, "2cos^2x-5sinx-4=0")' /><br />
<img class="pod_vlatex_inline" src="vlatex/pics/20_b3fed95ec75bf3e67a3cf86d80e330eb.png" alt="" title="Double click to see source code" style="vertical-align: -1.00pt;" onDblClick='vlatex_dblclick(this, "2-2sin^2x -5sinx-4=0")' /> ???<br />
<br />
are 1 and 2 correct? number 2 I wasn't sure about (sinx)^2=1/4 - - - sinx=1/2. can i just do a square root like that? and how do I solve 3?<br />
<br />
Thanks<!-- google_ad_section_end --></div>

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			<category domain="http://www.mathhelpforum.com/math-help/f14/">Trigonometry</category>
			<dc:creator>jayshizwiz</dc:creator>
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