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		<title>Math Help Forum - Discrete Mathematics, Set Theory and Logic</title>
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			<title>Math Help Forum - Discrete Mathematics, Set Theory and Logic</title>
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			<title>Find the last digit</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115788-find-last-digit.html</link>
			<pubDate>Fri, 20 Nov 2009 20:51:08 GMT</pubDate>
			<description><![CDATA[Find the last digit of 541^(341).  Clearly, the last digit would be one, but I don't know how to go about showing that it would be one.  Can someone help please?]]></description>
			<content:encoded><![CDATA[<div>Find the last digit of 541^(341).  Clearly, the last digit would be one, but I don't know how to go about showing that it would be one.  Can someone help please?</div>

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			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>steph3824</dc:creator>
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			<title>Delta-System Lemma counterexample</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115751-delta-system-lemma-counterexample.html</link>
			<pubDate>Fri, 20 Nov 2009 16:42:54 GMT</pubDate>
			<description><![CDATA[The \Delta-system lemma states the following: given an infinite cardinal \kappa, let \theta > \kappa be a regular cardinal such that \forall \alpha < \theta \ (|\alpha^{< \kappa}| < \theta); given A such that |A| \geq \theta and \forall x \in A \ (|x| < \kappa), then there is a B \subset A which...]]></description>
			<content:encoded><![CDATA[<div>The <a href="javascript:;" onclick="do_texpopup('\\Delta', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/967878d1da852d4b07a961e3168b0fff-1.gif" alt="\Delta" title="\Delta" style="border: 0px; vertical-align: middle;" /></a>-system lemma states the following: given an infinite cardinal <a href="javascript:;" onclick="do_texpopup('\\kappa', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/269cb4a8704d5fb203ad10436efe52d1-1.gif" alt="\kappa" title="\kappa" style="border: 0px; vertical-align: middle;" /></a>, let <a href="javascript:;" onclick="do_texpopup('\\theta &gt; \\kappa', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/3e178822f887290bf77a78db53cfd270-1.gif" alt="\theta &gt; \kappa" title="\theta &gt; \kappa" style="border: 0px; vertical-align: middle;" /></a> be a regular cardinal such that <a href="javascript:;" onclick="do_texpopup('\\forall \\alpha &lt; \\theta \\ (|\\alpha^{&lt; \\kappa}| &lt; \\theta)', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/91168c0a718138f69937680584186036-1.gif" alt="\forall \alpha &lt; \theta \ (|\alpha^{&lt; \kappa}| &lt; \theta)" title="\forall \alpha &lt; \theta \ (|\alpha^{&lt; \kappa}| &lt; \theta)" style="border: 0px; vertical-align: middle;" /></a>; given <a href="javascript:;" onclick="do_texpopup('A', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/7fc56270e7a70fa81a5935b72eacbe29-1.gif" alt="A" title="A" style="border: 0px; vertical-align: middle;" /></a> such that <a href="javascript:;" onclick="do_texpopup('|A| \\geq \\theta', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/dfed043a130e0083e79f1fa34610cffc-1.gif" alt="|A| \geq \theta" title="|A| \geq \theta" style="border: 0px; vertical-align: middle;" /></a> and <a href="javascript:;" onclick="do_texpopup('\\forall x \\in A \\ (|x| &lt; \\kappa)', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/3e795e55820b33dbfe1379c3bbb1237c-1.gif" alt="\forall x \in A \ (|x| &lt; \kappa)" title="\forall x \in A \ (|x| &lt; \kappa)" style="border: 0px; vertical-align: middle;" /></a>, then there is a <a href="javascript:;" onclick="do_texpopup('B \\subset A', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/95d8981b7d6497ec10f44dc8fbc98368-1.gif" alt="B \subset A" title="B \subset A" style="border: 0px; vertical-align: middle;" /></a> which forms a <a href="javascript:;" onclick="do_texpopup('\\Delta', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/967878d1da852d4b07a961e3168b0fff-1.gif" alt="\Delta" title="\Delta" style="border: 0px; vertical-align: middle;" /></a>-system, such that <a href="javascript:;" onclick="do_texpopup('|B| = \\theta', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/51d9e3b1e903b4da7fa20363e9088d96-1.gif" alt="|B| = \theta" title="|B| = \theta" style="border: 0px; vertical-align: middle;" /></a>.<br />
<br />
I wish to find a counterexample if <a href="javascript:;" onclick="do_texpopup('\\kappa', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/269cb4a8704d5fb203ad10436efe52d1-1.gif" alt="\kappa" title="\kappa" style="border: 0px; vertical-align: middle;" /></a> is not regular. For example, I wish to prove that there is a family <a href="javascript:;" onclick="do_texpopup('A', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/7fc56270e7a70fa81a5935b72eacbe29-1.gif" alt="A" title="A" style="border: 0px; vertical-align: middle;" /></a> with <a href="javascript:;" onclick="do_texpopup('|A| = \\omega_\\omega', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/d0a89c7f79e0b611fa4760942ded95a8-1.gif" alt="|A| = \omega_\omega" title="|A| = \omega_\omega" style="border: 0px; vertical-align: middle;" /></a> and <a href="javascript:;" onclick="do_texpopup('\\forall x \\in A \\ (|x| &lt; \\omega)', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/156743b9dea91c2abc81c1fc709de208-1.gif" alt="\forall x \in A \ (|x| &lt; \omega)" title="\forall x \in A \ (|x| &lt; \omega)" style="border: 0px; vertical-align: middle;" /></a> such that no <a href="javascript:;" onclick="do_texpopup('B \\subset A', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/95d8981b7d6497ec10f44dc8fbc98368-1.gif" alt="B \subset A" title="B \subset A" style="border: 0px; vertical-align: middle;" /></a> (with <a href="javascript:;" onclick="do_texpopup('|B| = \\omega_\\omega', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/07ef527c2921c3b96aba81551daf4972-1.gif" alt="|B| = \omega_\omega" title="|B| = \omega_\omega" style="border: 0px; vertical-align: middle;" /></a>) is a <a href="javascript:;" onclick="do_texpopup('\\Delta', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/967878d1da852d4b07a961e3168b0fff-1.gif" alt="\Delta" title="\Delta" style="border: 0px; vertical-align: middle;" /></a>-system.<br />
<br />
Every help is appreciated. Thanks.</div>

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			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>eurialo</dc:creator>
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			<title>quick question</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115741-quick-question.html</link>
			<pubDate>Fri, 20 Nov 2009 15:05:54 GMT</pubDate>
			<description>how could this one (-3)(2)^{n-1} + 2^n(-1) simplify to -2^{n+2}+3?</description>
			<content:encoded><![CDATA[<div>how could this one <a href="javascript:;" onclick="do_texpopup('(-3)(2)^{n-1} + 2^n(-1)', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/6783ada2c4106a3f346a0925b924cf6c-1.gif" alt="(-3)(2)^{n-1} + 2^n(-1)" title="(-3)(2)^{n-1} + 2^n(-1)" style="border: 0px; vertical-align: middle;" /></a> simplify to <a href="javascript:;" onclick="do_texpopup('-2^{n+2}+3', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/abe321b50350a0694530d1b7f9cccc81-1.gif" alt="-2^{n+2}+3" title="-2^{n+2}+3" style="border: 0px; vertical-align: middle;" /></a>?</div>

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			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>zpwnchen</dc:creator>
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			<title>Troubles with Quantificational Logic</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115715-troubles-quantificational-logic.html</link>
			<pubDate>Fri, 20 Nov 2009 10:43:45 GMT</pubDate>
			<description>I am having troubles converting some natural language sentences into quantificational statements. Any help would be greatly appreciated. 
 
1) The best is better than the worst (Fxy - x is better than y) 
 
2) Everyone loves a lover (Fx - x is a person, Gxy - x loves y) 
 
3) The God who begat...</description>
			<content:encoded><![CDATA[<div>I am having troubles converting some natural language sentences into quantificational statements. Any help would be greatly appreciated.<br />
<br />
1) The best is better than the worst (Fxy - x is better than y)<br />
<br />
2) Everyone loves a lover (Fx - x is a person, Gxy - x loves y)<br />
<br />
3) The God who begat Polyphemus begets only cyclopes. (Bxy - x begets y, Gx - x is a God, Cx - x is a cyclops, m - Polyphemus<br />
<br />
4) No two crooks are equally rich (Cx - x is a crook, Rxy - x is richer than y)</div>

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			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>Haven</dc:creator>
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			<title>problem to prove based on mathematical induction</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115705-problem-prove-based-mathematical-induction.html</link>
			<pubDate>Fri, 20 Nov 2009 08:30:05 GMT</pubDate>
			<description>Please give me the answer for the below question. 
  
prove that (2 pow n . 2 pow n) - 1 is divisible by 3 by mathematical induction.</description>
			<content:encoded><![CDATA[<div>Please give me the answer for the below question.<br />
 <br />
prove that (2 pow n . 2 pow n) - 1 is divisible by 3 by mathematical induction.</div>

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			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>sudeepmansh</dc:creator>
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			<title>permutation question</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115689-permutation-question.html</link>
			<pubDate>Fri, 20 Nov 2009 04:13:21 GMT</pubDate>
			<description>In how many ways can 5 different trees be planted in a circle. 
The answer is 24. I would think that it should be 5! but instead it is 4!? Does anyone understand this problem?</description>
			<content:encoded><![CDATA[<div>In how many ways can 5 different trees be planted in a circle.<br />
The answer is 24. I would think that it should be 5! but instead it is 4!? Does anyone understand this problem?</div>

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			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>modeselect</dc:creator>
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			<title>Stuck on Simple Inductive Proof</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115667-stuck-simple-inductive-proof.html</link>
			<pubDate>Fri, 20 Nov 2009 02:24:08 GMT</pubDate>
			<description>Show that for all n \geq 0,  
 3^{2n}+4^{n+1} is a mulitple of 5 using an inductive proof. 
 
I think that I have started this right but I am not sure if it is complete or correct. 
 
 1) \ p(0) = 3^{3(0)}+4^{(0)+1}=1+4=5 
 2) \ Assume \ p(n)= 3^{2n}+4^{n+1} \ is \ multiple \ of \ 5, 
 p(n+1) =...</description>
			<content:encoded><![CDATA[<div>Show that for all <a href="javascript:;" onclick="do_texpopup('n \\geq 0,', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/044db11354418fc067d13190b7aeef19-1.gif" alt="n \geq 0," title="n \geq 0," style="border: 0px; vertical-align: middle;" /></a><br />
<a href="javascript:;" onclick="do_texpopup('3^{2n}+4^{n+1}', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/9c02c5cf8db0dbf9b8e6446e469af95c-1.gif" alt="3^{2n}+4^{n+1}" title="3^{2n}+4^{n+1}" style="border: 0px; vertical-align: middle;" /></a> is a mulitple of 5 using an inductive proof.<br />
<br />
I think that I have started this right but I am not sure if it is complete or correct.<br />
<br />
<a href="javascript:;" onclick="do_texpopup('1) \\ p(0) = 3^{3(0)}+4^{(0)+1}=1+4=5', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/7d53f1aaa31d284ba03c7dfbbf5e3a1b-1.gif" alt="1) \ p(0) = 3^{3(0)}+4^{(0)+1}=1+4=5" title="1) \ p(0) = 3^{3(0)}+4^{(0)+1}=1+4=5" style="border: 0px; vertical-align: middle;" /></a><br />
<a href="javascript:;" onclick="do_texpopup('2) \\ Assume \\ p(n)= 3^{2n}+4^{n+1} \\ is \\ multiple \\ of \\ 5,', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/ab6ce14feb1cc2012715e513579c6d11-1.gif" alt="2) \ Assume \ p(n)= 3^{2n}+4^{n+1} \ is \ multiple \ of \ 5," title="2) \ Assume \ p(n)= 3^{2n}+4^{n+1} \ is \ multiple \ of \ 5," style="border: 0px; vertical-align: middle;" /></a><br />
<a href="javascript:;" onclick="do_texpopup('p(n+1) = p(n)+3^{2(n+1)}+4^{(n+1)+1}', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/2feb8004db56c94a118fb315bb636a5f-1.gif" alt="p(n+1) = p(n)+3^{2(n+1)}+4^{(n+1)+1}" title="p(n+1) = p(n)+3^{2(n+1)}+4^{(n+1)+1}" style="border: 0px; vertical-align: middle;" /></a><br />
<a href="javascript:;" onclick="do_texpopup('= 3^{2n}+4^{n+1}+3^{2n+2}+4^{n+2}', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/e2a89e266fe02e433fe323082571d553-1.gif" alt="= 3^{2n}+4^{n+1}+3^{2n+2}+4^{n+2}" title="= 3^{2n}+4^{n+1}+3^{2n+2}+4^{n+2}" style="border: 0px; vertical-align: middle;" /></a><br />
<a href="javascript:;" onclick="do_texpopup('= 3^{2n}+4^{n+1}+3^{2n}(9)+4^{n+1}(4)', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/779a80392a9566de6abe366b748dc7bc-1.gif" alt="= 3^{2n}+4^{n+1}+3^{2n}(9)+4^{n+1}(4)" title="= 3^{2n}+4^{n+1}+3^{2n}(9)+4^{n+1}(4)" style="border: 0px; vertical-align: middle;" /></a><br />
<a href="javascript:;" onclick="do_texpopup('= 3^{2n}(1+9)+4^{n+1}(1+4) \\ by \\ factoring', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/d3acb89bcf3fb433d1c21339837fc93c-1.gif" alt="= 3^{2n}(1+9)+4^{n+1}(1+4) \ by \ factoring" title="= 3^{2n}(1+9)+4^{n+1}(1+4) \ by \ factoring" style="border: 0px; vertical-align: middle;" /></a><br />
<a href="javascript:;" onclick="do_texpopup('= 3^{2n}(10)+4^{n+1}(5)', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/b97232faf9cd5fbb5244bafcede6d188-1.gif" alt="= 3^{2n}(10)+4^{n+1}(5)" title="= 3^{2n}(10)+4^{n+1}(5)" style="border: 0px; vertical-align: middle;" /></a><br />
<br />
So it appears to me that both terms are indeed multiples of 5; however, I thought the original p(n) would be factored out of the equation. In truth, it just looks a little funny. A little help or clarification would be greatly appreciated.</div>

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			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>b.rad</dc:creator>
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			<title>sentential logic derivations?</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115618-sentential-logic-derivations.html</link>
			<pubDate>Thu, 19 Nov 2009 20:06:04 GMT</pubDate>
			<description><![CDATA[how do i prove the following is a theorem in SD 
[(A -> B)->A]->A 
... i started off by assuming  [(A -> B)->A] then assume ~A to try to derive A in the end... but now i'm stuck :( 
 
and also: 
 
Suppose we dropped from SD the rule for vE, and adopted in its place the rule of Disjunctive Syllogism...]]></description>
			<content:encoded><![CDATA[<div>how do i prove the following is a theorem in SD<br />
[(A -&gt; B)-&gt;A]-&gt;A<br />
... i started off by assuming  [(A -&gt; B)-&gt;A] then assume ~A to try to derive A in the end... but now i'm stuck :(<br />
<br />
and also:<br />
<br />
Suppose we dropped from SD the rule for vE, and adopted in its place the rule of Disjunctive Syllogism (DS), thus giving a modified system SD. Show that<br />
you can derive the SD rule for vE in SD.<br />
<br />
I have no idea how to even approach the second question.. any help would be greatly appreciated.. thanks! :D</div>

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			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>cosmopolitanx</dc:creator>
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			<title>Chinese remainder theorem 2</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115585-chinese-remainder-theorem-2-a.html</link>
			<pubDate>Thu, 19 Nov 2009 16:35:42 GMT</pubDate>
			<description>Find all solutions, if any, to the system of congruences 
x \equiv 7 (mod 9) 
x \equiv 4 (mod 12) 
x \equiv 16 (mod 21) 
  
Solution manual states: We cannot apply the CRT directly, since the moduli are not pairwise relatively prime. (Got that on my own.) However, we can, using the CRT, translate...</description>
			<content:encoded><![CDATA[<div>Find all solutions, if any, to the system of congruences<br />
x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 7 (mod 9)<br />
x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 4 (mod 12)<br />
x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 16 (mod 21)<br />
 <br />
Solution manual states: We cannot apply the CRT directly, since the moduli are not pairwise relatively prime. (Got that on my own.) However, we can, using the CRT, translate these congruences into a set of congruences that together are equivalent to the given congruence. Since, we want x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 4 (mod 12), we must have x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 4 <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 1 (mod 3) and x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 4 <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 0 (mod 4).<br />
 <br />
<font color="red">First question, how do we convert congruences? I can see that dividing the 4 and 12 by 4 could give 1 (mod 3), is that the correct procedure? But I don't see how that equates to 0 (mod 4), could you help me there?</font><br />
 <br />
Similarly, from the third congruence we must have x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 1 (mod 3) and x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 2 (mod 7). <font color="red">Why? </font><br />
 <br />
<font color="black">From here I think I can solve the following system with the excellent help I've received previously.</font><br />
 <br />
x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 7 (mod 9)<br />
x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 0 (mod 4)<br />
x <a href="javascript:;" onclick="do_texpopup('\\equiv', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" alt="\equiv" title="\equiv" style="border: 0px; vertical-align: middle;" /></a> 2 (mod 7).<br />
 <br />
Thanks for any explanations.</div>

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			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>oldguynewstudent</dc:creator>
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			<title>Need help with a proof dealing with functions</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115583-need-help-proof-dealing-functions.html</link>
			<pubDate>Thu, 19 Nov 2009 16:10:05 GMT</pubDate>
			<description><![CDATA[Let f:A--->B be a function.  Prove that f is surjective if and only if f^(-1)(W) does not equal the empty set for all nonempty sets W of B. 
  
I really do not know what to do with this.  Thanks for your help everyone]]></description>
			<content:encoded><![CDATA[<div>Let f:A---&gt;B be a function.  Prove that f is surjective if and only if f^(-1)(W) does not equal the empty set for all nonempty sets W of B.<br />
 <br />
I really do not know what to do with this.  Thanks for your help everyone</div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>steph3824</dc:creator>
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			<title>Ordinal Arithmetic</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115576-ordinal-arithmetic.html</link>
			<pubDate>Thu, 19 Nov 2009 15:27:42 GMT</pubDate>
			<description>I have a question here on ordinal arithmetic: Suppose \alpha + \beta = \omega (\alpha, \beta not zero). What are \alpha \beta , \alpha^\beta? 
 
Am I right in assuming that the sum of two finite ordinals cannot be an infinite ordinal? If so I figure \beta = \omega  and \alpha can just be any finite...</description>
			<content:encoded><![CDATA[<div>I have a question here on ordinal arithmetic: Suppose <a href="javascript:;" onclick="do_texpopup('\\alpha + \\beta = \\omega', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/4ceb2e0815db8dc3cbea5c02d82bc2db-1.gif" alt="\alpha + \beta = \omega" title="\alpha + \beta = \omega" style="border: 0px; vertical-align: middle;" /></a> (<a href="javascript:;" onclick="do_texpopup('\\alpha, \\beta', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/b949fcc832c2ea997346d644870e0047-1.gif" alt="\alpha, \beta" title="\alpha, \beta" style="border: 0px; vertical-align: middle;" /></a> not zero). What are <a href="javascript:;" onclick="do_texpopup('\\alpha \\beta , \\alpha^\\beta', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/b4d53ee616ea5da0fcf9f67ea1594580-1.gif" alt="\alpha \beta , \alpha^\beta" title="\alpha \beta , \alpha^\beta" style="border: 0px; vertical-align: middle;" /></a>?<br />
<br />
Am I right in assuming that the sum of two finite ordinals cannot be an infinite ordinal? If so I figure <a href="javascript:;" onclick="do_texpopup('\\beta = \\omega', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/8caa2180dfb268ff7f92509903d35744-1.gif" alt="\beta = \omega" title="\beta = \omega" style="border: 0px; vertical-align: middle;" /></a> and <a href="javascript:;" onclick="do_texpopup('\\alpha', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/7b7f9dbfea05c83784f8b85149852f08-1.gif" alt="\alpha" title="\alpha" style="border: 0px; vertical-align: middle;" /></a> can just be any finite ordinal. So <a href="javascript:;" onclick="do_texpopup('\\alpha \\beta = \\omega', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/f057b45f1ba30a9376e6075baecfe102-1.gif" alt="\alpha \beta = \omega" title="\alpha \beta = \omega" style="border: 0px; vertical-align: middle;" /></a> and <a href="javascript:;" onclick="do_texpopup('\\alpha^\\beta = \\omega', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/ab9a2e249d4187e9983619fe5a507c47-1.gif" alt="\alpha^\beta = \omega" title="\alpha^\beta = \omega" style="border: 0px; vertical-align: middle;" /></a> (by two rules in my notes). <br />
<br />
Alpha and beta cannot be the other way round as right cancellation does not work.<br />
<br />
So I think this proof is sound if the first statement is true. If anyone can comment on what I've done that'd be neat.</div>

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			<dc:creator>whatisthisfor</dc:creator>
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			<title>my first problem</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115564-my-first-problem.html</link>
			<pubDate>Thu, 19 Nov 2009 14:33:58 GMT</pubDate>
			<description>let a1,a2,...........,an be n nubers such that each ai is either 1 or -1.if a1a2a3a4+a2a3a4a5+........+ana1a2a3=0, 
prove that 4 divides n 
  
  
pls give me a solution</description>
			<content:encoded><![CDATA[<div>let a1,a2,...........,an be n nubers such that each ai is either 1 or -1.if a1a2a3a4+a2a3a4a5+........+ana1a2a3=0,<br />
prove that 4 divides n<br />
 <br />
 <br />
pls give me a solution</div>

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			<category domain="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/">Discrete Mathematics, Set Theory and Logic</category>
			<dc:creator>arjun sengupta</dc:creator>
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			<title>problem on inclusion exclusion</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115559-problem-inclusion-exclusion.html</link>
			<pubDate>Thu, 19 Nov 2009 13:40:47 GMT</pubDate>
			<description>Please describe the way to find the answer for the following question. 
 
This problem is based on inclusion exclusion principle 
 
50 cars were assembled in a factory. The options available were radio, AC,  
power steering.  It is known that 20 of the cars have radios, 12 of them have  
AC and 10...</description>
			<content:encoded><![CDATA[<div>Please describe the way to find the answer for the following question.<br />
<br />
This problem is based on inclusion exclusion principle<br />
<br />
50 cars were assembled in a factory. The options available were radio, AC, <br />
power steering.  It is known that 20 of the cars have radios, 12 of them have <br />
AC and 10 of them have power steerings. 5 of them have all three options.  <br />
Determine at least how many cars do not have any options at all.</div>

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			<dc:creator>sudeepmansh</dc:creator>
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			<title>Points in a plane.</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115512-points-plane.html</link>
			<pubDate>Thu, 19 Nov 2009 05:14:57 GMT</pubDate>
			<description><![CDATA[These are based on a similar problem on this forum 
http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115382-points-plane-pigeonhole-principal.html 
 
1. Let there be 'some' points in a plane such that distance between any two them is < 1. What is the minimum area/shape...]]></description>
			<content:encoded><![CDATA[<div>These are based on a similar problem on this forum<br />
<a href="http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115382-points-plane-pigeonhole-principal.html" target="_blank">http://www.mathhelpforum.com/math-he...principal.html</a><br />
<br />
1. Let there be 'some' points in a plane such that distance between any two them is &lt; 1. What is the minimum area/shape which can inscribe all these points?<br />
<br />
2. You grab an area by putting infinite points on a plane. Only condition - any two points you put should be &lt;1 apart. What is the maximum area you can grab?<br />
<br />
Any pointers? I think I know the answer but am struggling to justify it.<br />
<br />
Thanks</div>

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			<dc:creator>aman_cc</dc:creator>
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			<title>Show that pos int divisible by 3 iff sum of digits divisible by 3</title>
			<link>http://www.mathhelpforum.com/math-help/discrete-mathematics-set-theory-logic/115509-show-pos-int-divisible-3-iff-sum-digits-divisible-3-a.html</link>
			<pubDate>Thu, 19 Nov 2009 04:48:53 GMT</pubDate>
			<description><![CDATA[Show that a positive integer is divisible by 3 iff the sum of its digits is divisible by 3. 
  
This is from Rosen but I can't follow the proof in the solutions manual (again). Section 3.6 problem 29. 
  
Please explain the detail so I'll understand the whole process.]]></description>
			<content:encoded><![CDATA[<div>Show that a positive integer is divisible by 3 iff the sum of its digits is divisible by 3.<br />
 <br />
This is from Rosen but I can't follow the proof in the solutions manual (again). Section 3.6 problem 29.<br />
 <br />
Please explain the detail so I'll understand the whole process.</div>

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			<dc:creator>oldguynewstudent</dc:creator>
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