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		<title>Math Help Forum - Calculus</title>
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			<title>Math Help Forum - Calculus</title>
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			<title>Cylindrical Can Optimization</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115802-cylindrical-can-optimization.html</link>
			<pubDate>Fri, 20 Nov 2009 21:58:41 GMT</pubDate>
			<description><![CDATA[This is my first post and involves optimization of the most economic shape of a can. The problem verbatim is "Let's assume that most of the expense is incurred in joining the sides to the rims of the cans. If we cut the discs from hexagons as in task #4, then the total cost is proportional to  
...]]></description>
			<content:encoded><![CDATA[<div>This is my first post and involves optimization of the most economic shape of a can. The problem verbatim is &quot;Let's assume that most of the expense is incurred in joining the sides to the rims of the cans. If we cut the discs from hexagons as in task #4, then the total cost is proportional to <br />
<br />
4*3^(1/3)r^2+2pirh+k(4pir+h)<br />
<br />
where k is the reciprocal of the length that can be joined for the cost of one unit area of metal. Show that this expression is minimized when:<br />
<br />
(V^1/3)/k= ((pih)/r)^1/3 * (2pi-h/r)/(pih/r-4*3^(1/3)<br />
<br />
I have no idea where to begin with this one. Any help is much appreciated.</div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>heebee</dc:creator>
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			<title>Computing Residue</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115789-computing-residue.html</link>
			<pubDate>Fri, 20 Nov 2009 20:53:15 GMT</pubDate>
			<description><![CDATA[I need to compute the residue for \frac{e^{-z}}{(z-1)^2}. I'm going to be using it for Cauchy's residue theorem to evaluate the integral around the circle |z| = 3, so there is obviously a singularity at z=1. I'm confused how to manipulate the fraction and bring in series so that I can see what the...]]></description>
			<content:encoded><![CDATA[<div>I need to compute the residue for <a href="javascript:;" onclick="do_texpopup('\\frac{e^{-z}}{(z-1)^2}', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/08835a9088d65233e1c6707d7f676d8e-1.gif" alt="\frac{e^{-z}}{(z-1)^2}" title="\frac{e^{-z}}{(z-1)^2}" style="border: 0px; vertical-align: middle;" /></a>. I'm going to be using it for Cauchy's residue theorem to evaluate the integral around the circle |z| = 3, so there is obviously a singularity at z=1. I'm confused how to manipulate the fraction and bring in series so that I can see what the coefficient on the <a href="javascript:;" onclick="do_texpopup('\\frac{1}{z-1}', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/1b68607b60fb394b1ed43f62b148b2ae-1.gif" alt="\frac{1}{z-1}" title="\frac{1}{z-1}" style="border: 0px; vertical-align: middle;" /></a> term. Thank you.</div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>azdang</dc:creator>
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			<title>Differentiation problems</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115778-differentiation-problems.html</link>
			<pubDate>Fri, 20 Nov 2009 20:11:12 GMT</pubDate>
			<description>Hey i am having a bit of trouble with these differentiation problems; 
 
1. Find the equation to the tangent to y=e^-x, at the point where x = 1 
2. Find the equation to the tangent to y= ln(2-x) at the point where x = -1 
3. The tangent at x = 1 to y = x^2e^x cuts the x and y axis at  A and B...</description>
			<content:encoded><![CDATA[<div>Hey i am having a bit of trouble with these differentiation problems;<br />
<br />
1. Find the equation to the tangent to y=e^-x, at the point where x = 1<br />
2. Find the equation to the tangent to y= ln(2-x) at the point where x = -1<br />
3. The tangent at x = 1 to y = x^2e^x cuts the x and y axis at  A and B respectively. Find the coordinate of A and B<br />
4. Find the equation of the normal to y = ln  &#8730;  x at the point where y = -1<br />
<br />
Im not sure about any of these but for the first 2 i think you have to differentiate first but im nt really sure..<br />
<br />
thanks!</div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>Jampop</dc:creator>
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			<title>Find the integral</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115772-find-integral.html</link>
			<pubDate>Fri, 20 Nov 2009 18:31:17 GMT</pubDate>
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			<content:encoded><![CDATA[<div><u><img src="http://i47.tinypic.com/zsn3bd.jpg" border="0" alt="" /></u></div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>racewithferrari</dc:creator>
			<guid isPermaLink="true">http://www.mathhelpforum.com/math-help/calculus/115772-find-integral.html</guid>
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			<title>Do I need to change this into parametric form?</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115771-do-i-need-change-into-parametric-form.html</link>
			<pubDate>Fri, 20 Nov 2009 18:31:10 GMT</pubDate>
			<description><![CDATA[I need to find the points on: 
 
x^2+\frac{y^2}{4}+\frac{z^2}{9}=1 
 
where the tangent line is parallel to: 
 
x+2y+z=0 
 
 
This is what I've done:]]></description>
			<content:encoded><![CDATA[<div>I need to find the points on:<br />
<br />
<a href="javascript:;" onclick="do_texpopup('x^2+\\frac{y^2}{4}+\\frac{z^2}{9}=1', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/64ffd2097c68273c65bd57937f3277e9-1.gif" alt="x^2+\frac{y^2}{4}+\frac{z^2}{9}=1" title="x^2+\frac{y^2}{4}+\frac{z^2}{9}=1" style="border: 0px; vertical-align: middle;" /></a><br />
<br />
where the tangent line is parallel to:<br />
<br />
<a href="javascript:;" onclick="do_texpopup('x+2y+z=0', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/312506170d710396cc132af344031973-1.gif" alt="x+2y+z=0" title="x+2y+z=0" style="border: 0px; vertical-align: middle;" /></a><br />
<br />
<br />
This is what I've done:<br />
<br />
<a href="javascript:;" onclick="do_texpopup('\\langle 2x, \\frac{y}{4}, \\frac{2z}{9} \\rangle \\cdot \\langle 1,2,1 \\rangle =0', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/18ff74bb8d222d9aaf240bd5fd529879-1.gif" alt="\langle 2x, \frac{y}{4}, \frac{2z}{9} \rangle \cdot \langle 1,2,1 \rangle =0" title="\langle 2x, \frac{y}{4}, \frac{2z}{9} \rangle \cdot \langle 1,2,1 \rangle =0" style="border: 0px; vertical-align: middle;" /></a><br />
<br />
<a href="javascript:;" onclick="do_texpopup('=2x+y+\\frac{2z}{9}=0', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/14d62d0219c8b5f41fce13b4df420540-1.gif" alt="=2x+y+\frac{2z}{9}=0" title="=2x+y+\frac{2z}{9}=0" style="border: 0px; vertical-align: middle;" /></a><br />
<br />
Not sure what to do now... do I have to change this to parametric form?  Should I have changed it first?</div>

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			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>MathSucker</dc:creator>
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			<title>Calculus Intergral......Evaluating the Riemann sum</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115770-calculus-intergral-evaluating-riemann-sum.html</link>
			<pubDate>Fri, 20 Nov 2009 18:30:13 GMT</pubDate>
			<description>Image: http://i47.tinypic.com/skxqh5.jpg</description>
			<content:encoded><![CDATA[<div><img src="http://i47.tinypic.com/skxqh5.jpg" border="0" alt="" /></div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>racewithferrari</dc:creator>
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			<title>Another line integral question....</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115769-another-line-integral-question.html</link>
			<pubDate>Fri, 20 Nov 2009 18:26:38 GMT</pubDate>
			<description><![CDATA[Evaluate the line integral directly, WITHOUT using Green's theorem. 
 
Integral of (x-y)dx+(x+y)dy where C is the circle with center the origin and radius 2. 
 
I have to show that both methods give me the same answer. I know how to do it with Green's theorem...but not otherwise.]]></description>
			<content:encoded><![CDATA[<div>Evaluate the line integral directly, WITHOUT using Green's theorem.<br />
<br />
Integral of (x-y)dx+(x+y)dy where C is the circle with center the origin and radius 2.<br />
<br />
I have to show that both methods give me the same answer. I know how to do it with Green's theorem...but not otherwise.</div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>daskywalker</dc:creator>
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			<title><![CDATA[L'Hospital's rule]]></title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115765-lhospitals-rule.html</link>
			<pubDate>Fri, 20 Nov 2009 17:55:27 GMT</pubDate>
			<description><![CDATA[Can anyone explain the procedures in solving these two problems using L'Hospital's rule? 
  
1. lim x-> 0+ (tan 2x)^x 
  
2. lim x-> 1 (2 - x)^tan((pi)x/2)]]></description>
			<content:encoded><![CDATA[<div>Can anyone explain the procedures in solving these two problems using L'Hospital's rule?<br />
 <br />
1. lim x-&gt; 0+ (tan 2x)^x<br />
 <br />
2. lim x-&gt; 1 (2 - x)^tan((pi)x/2)</div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>Eternal</dc:creator>
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			<title>Newton-Raphson Theorem Third Repetition Confirmation</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115758-newton-raphson-theorem-third-repetition-confirmation.html</link>
			<pubDate>Fri, 20 Nov 2009 17:34:21 GMT</pubDate>
			<description>Hi, 
 
Can anyone confirm for me that the third Newton-Raphson repetition of f(x)=e^x+10x-3 at x=0 is approximately 0.18025?</description>
			<content:encoded><![CDATA[<div>Hi,<br />
<br />
Can anyone confirm for me that the third Newton-Raphson repetition of <a href="javascript:;" onclick="do_texpopup('f(x)=e^x+10x-3', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/37b53a16024d23f1cfb7cc38c6cf8d0f-1.gif" alt="f(x)=e^x+10x-3" title="f(x)=e^x+10x-3" style="border: 0px; vertical-align: middle;" /></a> at x=0 is approximately 0.18025?</div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>Kataangel</dc:creator>
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			<title>Taylor Polynomial Confirmation</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115757-taylor-polynomial-confirmation.html</link>
			<pubDate>Fri, 20 Nov 2009 17:28:20 GMT</pubDate>
			<description>Hi, 
 
Can anyone confirm for me that third Taylor Polynomial of f(x)=\sqrt{1-x} at x=0 is 1-\frac{1}{2}x-\frac{1}{8}x^2-\frac{1}{16}x^3 
 
Or P3(0)=1?</description>
			<content:encoded><![CDATA[<div>Hi,<br />
<br />
Can anyone confirm for me that third Taylor Polynomial of <a href="javascript:;" onclick="do_texpopup('f(x)=\\sqrt{1-x}', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/56cc14bed50339805f9f3fc6c7fb3a0f-1.gif" alt="f(x)=\sqrt{1-x}" title="f(x)=\sqrt{1-x}" style="border: 0px; vertical-align: middle;" /></a> at x=0 is <a href="javascript:;" onclick="do_texpopup('1-\\frac{1}{2}x-\\frac{1}{8}x^2-\\frac{1}{16}x^3', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/8da8b8a5e4206358972fcfd4be009a37-1.gif" alt="1-\frac{1}{2}x-\frac{1}{8}x^2-\frac{1}{16}x^3" title="1-\frac{1}{2}x-\frac{1}{8}x^2-\frac{1}{16}x^3" style="border: 0px; vertical-align: middle;" /></a><br />
<br />
Or P3(0)=1?</div>

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			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>Kataangel</dc:creator>
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			<title>Fundamental Theorem of Calculus to find the derivative of the function</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115756-fundamental-theorem-calculus-find-derivative-function.html</link>
			<pubDate>Fri, 20 Nov 2009 17:28:06 GMT</pubDate>
			<description>Image: http://i45.tinypic.com/25irwir.jpg  
 (http://i50.tinypic.com/23keykn.jpg)</description>
			<content:encoded><![CDATA[<div><a href="http://i50.tinypic.com/23keykn.jpg" target="_blank"><img src="http://i45.tinypic.com/25irwir.jpg" border="0" alt="" /><br />
</a></div>

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			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>racewithferrari</dc:creator>
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			<title>Surface Integral Help</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115754-surface-integral-help.html</link>
			<pubDate>Fri, 20 Nov 2009 17:16:07 GMT</pubDate>
			<description>The figure shows the surface created when the cylinder\ y^2 + z^2 = 1\ intersects\ the\ cylinder\ x^2 + z^2 = 1\ Find\ the\ area\ of\ this\ surface. 
 
I think to find the surface integral we need to do the double integral of ru cross rv, with respect to du and dv respectively. However, im not even...</description>
			<content:encoded><![CDATA[<div>The figure shows the surface created when the <a href="javascript:;" onclick="do_texpopup('cylinder\\ y^2 + z^2 = 1\\ intersects\\ the\\ cylinder\\ x^2 + z^2 = 1\\ Find\\ the\\ area\\ of\\ this\\ surface.', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/899c76cc8d665319efbcf6fbebd9795c-1.gif" alt="cylinder\ y^2 + z^2 = 1\ intersects\ the\ cylinder\ x^2 + z^2 = 1\ Find\ the\ area\ of\ this\ surface." title="cylinder\ y^2 + z^2 = 1\ intersects\ the\ cylinder\ x^2 + z^2 = 1\ Find\ the\ area\ of\ this\ surface." style="border: 0px; vertical-align: middle;" /></a><br />
<br />
I think to find the surface integral we need to do the double integral of ru cross rv, with respect to du and dv respectively. However, im not even sure how to get to that point.</div>


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			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>purplerain</dc:creator>
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			<title>I am confused on the steps for optimization, could someone please help</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115750-i-am-confused-steps-optimization-could-someone-please-help.html</link>
			<pubDate>Fri, 20 Nov 2009 16:36:26 GMT</pubDate>
			<description>Here is the sample problem (but the object will change for the test): 
 
Optimization.The base b and height h of an isosceles triangle vary in such 
a way that its perimeter,is constant,and equal to 6. Find the maximum possible area of the triangle. 
 
What I know from this: 
P=B * 2S  (base times...</description>
			<content:encoded><![CDATA[<div>Here is the sample problem (but the object will change for the test):<br />
<br />
Optimization.The base b and height h of an isosceles triangle vary in such<br />
a way that its perimeter,is constant,and equal to 6. Find the maximum possible area of the triangle.<br />
<br />
What I know from this:<br />
P=B * 2S  (base times the 2 sides)<br />
P=6<br />
A=BH (base times height)<br />
<br />
From the question I also think that I will be needing to find f' and f'' to find the maximimum area for the triangle, but I am not sure on that. <br />
<br />
I always get confused on the steps to work through optimization word problems.  Can someone please help?  I understand more if there is a step by step process to solve something.</div>

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			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>operaphantom2003</dc:creator>
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			<title>Partial fraction question</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115743-partial-fraction-question.html</link>
			<pubDate>Fri, 20 Nov 2009 15:43:41 GMT</pubDate>
			<description>I need help solving: 
  
integral of (20x-30) / (x(x-2)(x^2-2x+5)) 
  
If I try to decompose it; 
  
I will have 
  
LHS from above = (A/x)+(B/x-2) + ?</description>
			<content:encoded><![CDATA[<div>I need help solving:<br />
 <br />
integral of (20x-30) / (x(x-2)(x^2-2x+5))<br />
 <br />
<font color="#aa0000">If I try to decompose it;</font><br />
 <br />
<font color="#aa0000">I will have</font><br />
 <br />
<font color="#aa0000"><font color="#aa0000"><font size="3">LHS from above = (A/x)+(B/x-2) + ?</font></font><br />
 <br />
<font color="#aa0000"><font size="3">Stuck here.</font></font><br />
</font></div>

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			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
			<dc:creator>shadow85</dc:creator>
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			<title>Derivatives</title>
			<link>http://www.mathhelpforum.com/math-help/calculus/115739-derivatives.html</link>
			<pubDate>Fri, 20 Nov 2009 14:40:07 GMT</pubDate>
			<description>Find derivative dy/dx if  
  
a) y=tan^-1(1/2x) 
  
b) y=4^(-x+3) 
  
thanks!</description>
			<content:encoded><![CDATA[<div>Find derivative dy/dx if <br />
 <br />
a) y=tan^-1(1/2x)<br />
 <br />
b) y=4^(-x+3)<br />
 <br />
thanks!</div>

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			<category domain="http://www.mathhelpforum.com/math-help/calculus/">Calculus</category>
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