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			<title>Math Help Forum - Number theory</title>
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			<title>Getting stuck on the CRT</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115803-getting-stuck-crt.html</link>
			<pubDate>Fri, 20 Nov 2009 22:02:38 GMT</pubDate>
			<description><![CDATA[Ok, here's the problem. 
xImage: http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif  (http://www.mathhelpforum.com/math-help/JSREPL98326:;) 2 (mod 5) 
xImage: http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif ...]]></description>
			<content:encoded><![CDATA[<div>Ok, here's the problem.<br />
x<a href="http://www.mathhelpforum.com/math-help/JSREPL98326:;" target="_blank"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" border="0" alt="" /></a> 2 (mod 5)<br />
x<a href="http://www.mathhelpforum.com/math-help/JSREPL98326:;" target="_blank"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" border="0" alt="" /></a> 1 (mod 7)<br />
x<a href="http://www.mathhelpforum.com/math-help/JSREPL98326:;" target="_blank"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" border="0" alt="" /></a> 3 (mod 11)<br />
 <br />
Here is what I have so far..<br />
 <br />
M=5x7x11=385<br />
 <br />
M1=385/5=77<br />
m2=385/7=55<br />
M3=385/11=35<br />
 <br />
x=(a1xM1xy1)+(a2xM2xy2)+(a3xM3xy3)<br />
 <br />
77y1<a href="http://www.mathhelpforum.com/math-help/JSREPL98326:;" target="_blank"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" border="0" alt="" /></a> 1 (mod 5)<br />
55y2<a href="http://www.mathhelpforum.com/math-help/JSREPL98326:;" target="_blank"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" border="0" alt="" /></a> 1 (mod 7)<br />
35y3<a href="http://www.mathhelpforum.com/math-help/JSREPL98326:;" target="_blank"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" border="0" alt="" /></a> 1 (mod 11)<br />
 <br />
The issue I am having is getting the correct numbers for y1,y2,y3. What I am doing is using the Extended Euclidean Algorithm, but I'm not getting the numbers that are shown in my book, so I'm thinking that using the Extended Euclidean Algorithm isn't the proper way to figure out what the y's are. SO for example..I know that the solution to 77y1<a href="http://www.mathhelpforum.com/math-help/JSREPL98326:;" target="_blank"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" border="0" alt="" /></a> 1 (mod 5) is 3(mod 5), I just don't know where the 3 is coming from.<br />
 <br />
I hope this has all made sense, I explained this as clearly as possible!! Thanks for the help!</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>steph3824</dc:creator>
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			<title>Numbers in array and its exponents ( congruence operation )</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115793-numbers-array-its-exponents-congruence-operation.html</link>
			<pubDate>Fri, 20 Nov 2009 21:21:27 GMT</pubDate>
			<description>Introduction: 
============= 
 
Another way to see congruences is to put the numbers in an array of width n. 
In the following example n is 5: 
 
col     1   2   3   4   5 
-------------------------- 
        1   2   3   4   5 
        6   7   8   9   10</description>
			<content:encoded><![CDATA[<div><font face="Fixedsys">Introduction:<br />
=============<br />
<br />
Another way to see congruences is to put the numbers in an array of width n.<br />
In the following example n is 5:<br />
<br />
col     1   2   3   4   5<br />
--------------------------<br />
        1   2   3   4   5<br />
        6   7   8   9   10<br />
        11  12  13  14  15<br />
        16  17  18  19  20<br />
        21  22  23  24  25<br />
        26  27  28  29  30<br />
        31  32  33  34  35<br />
        36  37  38  39  40<br />
<br />
Numbers in the same column are congruent module 5, for instance 13 and 18<br />
are in the same column (3) so they are congruent mod 5,<br />
both gives 3 as a remainder when divided by 5.<br />
<br />
This way is very simple to see how some congruence operations work,<br />
for instance, two numbers will go together to the same column if I add a number x to<br />
them ( if x is 3, then 13+3=16 and 18+3 is 21, 16 and 21 now are on column 1 )<br />
<br />
What I am interested in:<br />
========================<br />
<br />
Lets look at the exponent operation, get number 2 in the table above, it is<br />
on column 2, now lets see in what columns 2^x result lands:<br />
<br />
2^1 = 2     ( column 2)<br />
2^2 = 4     ( column 4)<br />
2^3 = 8     ( column 3)<br />
2^4 = 16    ( column 1)<br />
2^5 = 32    ( column 2)<br />
<br />
The results landed in all possible columns, except 5, before it went back to<br />
its initial column 2.<br />
<br />
I read that if the number I chose is coprime with n ( 2 and 5 are coprime in<br />
my example ) the exponent results would land in all possible columns (except n)<br />
before repeating a column.<br />
<br />
Question:<br />
=========<br />
<br />
How can this be proved ?<br />
<br />
Thanks,<br />
</font></div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>jmarchetti</dc:creator>
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			<title>pythagorean triangles.</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115780-pythagorean-triangles.html</link>
			<pubDate>Fri, 20 Nov 2009 20:13:47 GMT</pubDate>
			<description>prove 12 divides product of legs 
 
 
prove 60 divides product of sides</description>
			<content:encoded><![CDATA[<div>prove 12 divides product of legs<br />
<br />
<br />
prove 60 divides product of sides</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>stumped765</dc:creator>
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			<title>Prove by contradiction</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115764-prove-contradiction.html</link>
			<pubDate>Fri, 20 Nov 2009 17:55:20 GMT</pubDate>
			<description>Prove by contradiction that if r is irrational, then r^(1/2) is irrational</description>
			<content:encoded><![CDATA[<div>Prove by contradiction that if r is irrational, then r^(1/2) is irrational</div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>hebby</dc:creator>
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			<title>Prove by contradiction</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115762-prove-contradiction.html</link>
			<pubDate>Fri, 20 Nov 2009 17:49:35 GMT</pubDate>
			<description>Prove by contradiction that 2^(1/3) is irrational. 
  
I made a=2^(1/3). 
  
a^2= 2^(2/3) 
  
then 2^(2/3)= _M^2  _  because we assume a is rational 
                     N^2   
then what do I do</description>
			<content:encoded><![CDATA[<div>Prove by contradiction that 2^(1/3) is irrational.<br />
 <br />
I made a=2^(1/3).<br />
 <br />
a^2= 2^(2/3)<br />
 <br />
then 2^(2/3)= <u>M^2  </u>  because we assume a is rational<br />
                     N^2  <br />
then what do I do</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>hebby</dc:creator>
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			<title>one more quadratic residue congruence problem please</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115738-one-more-quadratic-residue-congruence-problem-please.html</link>
			<pubDate>Fri, 20 Nov 2009 14:30:43 GMT</pubDate>
			<description>---Quote--- 
Prove that if p is an odd prime then x^2\equiv 2\mod p has solutions if and only if p\equiv1 or 7\mod 8. 
---End Quote--- 
This exercise comes in the chapter on quadratic residues and the Legendre symbol.  I have absolutely no idea how to prove what it asks.  None of the theorems in...</description>
			<content:encoded><![CDATA[<div><div style="margin:20px; margin-top:5px; ">
	<div class="smallfont" style="margin-bottom:2px">Quote:</div>
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			<hr />
			
				Prove that if <a href="javascript:;" onclick="do_texpopup('p', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/83878c91171338902e0fe0fb97a8c47a-1.gif" alt="p" title="p" style="border: 0px; vertical-align: middle;" /></a> is an odd prime then <a href="javascript:;" onclick="do_texpopup('x^2\\equiv 2\\mod p', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/19cd13c9001423d5c9e69c7a05204ebf-1.gif" alt="x^2\equiv 2\mod p" title="x^2\equiv 2\mod p" style="border: 0px; vertical-align: middle;" /></a> has solutions if and only if <a href="javascript:;" onclick="do_texpopup('p\\equiv1', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/0ea628c43f66d36c8200885cad17c4f2-1.gif" alt="p\equiv1" title="p\equiv1" style="border: 0px; vertical-align: middle;" /></a> or <a href="javascript:;" onclick="do_texpopup('7\\mod 8', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/3059c0a2dfc23569154fc204ac03a70d-1.gif" alt="7\mod 8" title="7\mod 8" style="border: 0px; vertical-align: middle;" /></a>.
			
			<hr />
		</td>
	</tr>
	</table>
</div>This exercise comes in the chapter on quadratic residues and the Legendre symbol.  I have absolutely no idea how to prove what it asks.  None of the theorems in the chapter seem relevant.<br />
<br />
My professor has been skipping around in the book, and blending in his own material.  I suspect he may have skipped over something from an earlier chapter, which I need to solve this.<br />
<br />
Hints or useful theorems would be much appreciated.</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>hatsoff</dc:creator>
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			<title><![CDATA[[SOLVED] quadratic residues congruence problem]]></title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115639-solved-quadratic-residues-congruence-problem.html</link>
			<pubDate>Thu, 19 Nov 2009 23:23:37 GMT</pubDate>
			<description><![CDATA[---Quote--- 
list all solutions of...the ten congruences x^2\equiv a\mod 11^2 where a=1,3,4,5,9. 
---End Quote--- 
We know that each congruence has two solutions, and that if we can find one solution x\equiv s then the second solution is x\equiv-s.  But I don't know any algorithms I can use to...]]></description>
			<content:encoded><![CDATA[<div><div style="margin:20px; margin-top:5px; ">
	<div class="smallfont" style="margin-bottom:2px">Quote:</div>
	<table cellpadding="6" cellspacing="0" border="0" width="100%">
	<tr>
		<td class="alt2">
			<hr />
			
				list all solutions of...the ten congruences <a href="javascript:;" onclick="do_texpopup('x^2\\equiv a\\mod 11^2', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/c0e67d2ad3e2561c968448a0897ee523-1.gif" alt="x^2\equiv a\mod 11^2" title="x^2\equiv a\mod 11^2" style="border: 0px; vertical-align: middle;" /></a> where <a href="javascript:;" onclick="do_texpopup('a=1,3,4,5,9', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/249773ab2b06dd79810e86b17b1cdcdb-1.gif" alt="a=1,3,4,5,9" title="a=1,3,4,5,9" style="border: 0px; vertical-align: middle;" /></a>.
			
			<hr />
		</td>
	</tr>
	</table>
</div>We know that each congruence has two solutions, and that if we can find one solution <a href="javascript:;" onclick="do_texpopup('x\\equiv s', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/12d0b99eb0108e759c8927f29c0b99da-1.gif" alt="x\equiv s" title="x\equiv s" style="border: 0px; vertical-align: middle;" /></a> then the second solution is <a href="javascript:;" onclick="do_texpopup('x\\equiv-s', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/b0e0e9d89341a510fbffd8e3bfb6fae5-1.gif" alt="x\equiv-s" title="x\equiv-s" style="border: 0px; vertical-align: middle;" /></a>.  But I don't know any algorithms I can use to solve each of the first solutions, except trial and error, which of course is far too inefficient.<br />
<br />
This is an exercise in the chapter for quadratic residues, so presumably that has something to do with it.<br />
<br />
Any ideas would be appreciated.</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>hatsoff</dc:creator>
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			<title>Linear Congruences</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115582-linear-congruences.html</link>
			<pubDate>Thu, 19 Nov 2009 16:04:08 GMT</pubDate>
			<description><![CDATA[How do i prove that for every prime p > 5, the following system has a solution: 
 
7x + 3y = 1 mod p 
4x + 6y = -1 mod p]]></description>
			<content:encoded><![CDATA[<div>How do i prove that for every prime p &gt; 5, the following system has a solution:<br />
<br />
7x + 3y = 1 mod p<br />
4x + 6y = -1 mod p</div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>Zero266</dc:creator>
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			<title>Solve congruence using primitive root</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115549-solve-congruence-using-primitive-root.html</link>
			<pubDate>Thu, 19 Nov 2009 10:56:24 GMT</pubDate>
			<description><![CDATA[Hi, I have to solve this congruence 
  
*y^5 \equiv -1(mod22)* 
  
Now i've worked out that 7 is a primitive root mod 22. And y=7 is a solution. But shouldn't there be 5 solutions? How do I find the rest? 
  
I have tried using the fact that because (y,22)=1 if y is a solution, then  
  
y...]]></description>
			<content:encoded><![CDATA[<div>Hi, I have to solve this congruence<br />
 <br />
<b><a href="javascript:;" onclick="do_texpopup('y^5 \\equiv -1(mod22)', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/fb92f280ed59422fd1e28ab80307113a-1.gif" alt="y^5 \equiv -1(mod22)" title="y^5 \equiv -1(mod22)" style="border: 0px; vertical-align: middle;" /></a></b><br />
 <br />
Now i've worked out that 7 is a primitive root mod 22. And y=7 is a solution. But shouldn't there be 5 solutions? How do I find the rest?<br />
 <br />
I have tried using the fact that because (y,22)=1 if y is a solution, then <br />
 <br />
<a href="javascript:;" onclick="do_texpopup('y \\equiv{7^k}(mod22)', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/1601c939b6c2b36f3c38de857449bcff-1.gif" alt="y \equiv{7^k}(mod22)" title="y \equiv{7^k}(mod22)" style="border: 0px; vertical-align: middle;" /></a><br />
 <br />
to give me <br />
 <br />
<a href="javascript:;" onclick="do_texpopup('7^{5k} \\equiv{-1}(mod22)', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/8cfd0eec34a92adac8c5f736052082b6-1.gif" alt="7^{5k} \equiv{-1}(mod22)" title="7^{5k} \equiv{-1}(mod22)" style="border: 0px; vertical-align: middle;" /></a> <br />
 <br />
but i'm not sure if this gets me anywhere,<br />
 <br />
Please help.<br />
Katy :)</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>harkapobi</dc:creator>
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			<title>Set theory clarification</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115478-set-theory-clarification.html</link>
			<pubDate>Thu, 19 Nov 2009 01:36:27 GMT</pubDate>
			<description>A = { a, b, c, d, e, f, g} 
Expression: x = y           such that x, y are in A 
 
can x in A refer to the same thing as y in A or can it necessarily not because of the notation x, y in A?</description>
			<content:encoded><![CDATA[<div>A = { a, b, c, d, e, f, g}<br />
Expression: x = y           such that x, y are in A<br />
<br />
can x in A refer to the same thing as y in A or can it necessarily not because of the notation x, y in A?</div>

]]></content:encoded>
			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>Noxide</dc:creator>
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			<title><![CDATA[[SOLVED] Valid Proof? I DONT THINK SO...]]></title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115449-solved-valid-proof-i-dont-think-so.html</link>
			<pubDate>Wed, 18 Nov 2009 23:37:58 GMT</pubDate>
			<description>How the heck is the following a valid proof for: 
 
Show that the relation R on the integers defined by (x, y) in R if and only if y = 2x  is antisymmetric 
 
Proof: 
 
Suppose (x, y) in R and (y, x) in R 
To show: x = y 
 
Since (x,y) in R , y = 2x</description>
			<content:encoded><![CDATA[<div>How the heck is the following a valid proof for:<br />
<br />
Show that the relation R on the integers defined by (x, y) in R if and only if y = 2x  is antisymmetric<br />
<br />
Proof:<br />
<br />
Suppose (x, y) in R and (y, x) in R<br />
To show: x = y<br />
<br />
Since (x,y) in R , y = 2x<br />
Since (y, x) in R, x = 2y<br />
therefore y = 2x = 2(2y) = 4y<br />
<br />
THE FOLLOWING MAKES NO SENSE AT ALL<br />
<br />
therefore 3y = 0<br />
therefore y = 0<br />
therefore x = 2y = (2)(0) = 0<br />
therefore x = y , and R is antisymmetric<br />
<br />
This makes no sense at all. AT ALL.<br />
I other than 0,0 i cannot find a pair in this relation that would be antisymmetric...<br />
is a whole freaking relation antisymmetric if i can find one pair in it that is?<br />
So frustrated.<br />
<br />
PLEASE HELP</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>Noxide</dc:creator>
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			<title>Need help understanding the Chinese Remainder Theorem</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115429-need-help-understanding-chinese-remainder-theorem.html</link>
			<pubDate>Wed, 18 Nov 2009 22:46:42 GMT</pubDate>
			<description>Here is a simple example. 
  
xImage: http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif  (http://www.mathhelpforum.com/math-help/JSREPL98326:;) 11 (mod 39) 
xImage: http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif ...</description>
			<content:encoded><![CDATA[<div>Here is a simple example.<br />
 <br />
x<a href="http://www.mathhelpforum.com/math-help/JSREPL98326:;" target="_blank"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" border="0" alt="" /></a> 11 (mod 39)<br />
x<a href="http://www.mathhelpforum.com/math-help/JSREPL98326:;" target="_blank"><img src="http://www.mathhelpforum.com/math-help/latex2/img/851ffc531f462fd9c1fd2bcc1340c453-1.gif" border="0" alt="" /></a> 7 (mod 22)<br />
 <br />
I would greatly appreciate it if someone could explain how to do this.  I know first of all that 39a+22b=1.  I believe you are supposed to use Euclid's Algorithm right?  I know how to do Euclid's Algorithm I just don't understand how to use it to solve the problem I have shown above.  Please explain as much as you can, big test coming up soon!</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>steph3824</dc:creator>
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			<title>Prove x^4 - x^2 + 1 is reducible over F_p for all p</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115420-prove-x-4-x-2-1-reducible-over-f_p-all-p.html</link>
			<pubDate>Wed, 18 Nov 2009 21:50:51 GMT</pubDate>
			<description><![CDATA[Prove that x^4 - x^2 + 1 is reducible over \mathbb{F}_p for every prime p. 
 
I know x^4 - x^2 + 1 is the 12th cyclotomic polynomial and know a few properties of such polynomials, but I'm not sure if that really helps here. I can also show that p^2 -1 is divisible by 12 for p>3 but can't seem to...]]></description>
			<content:encoded><![CDATA[<div>Prove that <a href="javascript:;" onclick="do_texpopup('x^4 - x^2 + 1', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/77351f3c82b89e09953d491f1315a22a-1.gif" alt="x^4 - x^2 + 1" title="x^4 - x^2 + 1" style="border: 0px; vertical-align: middle;" /></a> is reducible over <a href="javascript:;" onclick="do_texpopup('\\mathbb{F}_p', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/03a0cc58ab774f8680e9fd94d5caf7b5-1.gif" alt="\mathbb{F}_p" title="\mathbb{F}_p" style="border: 0px; vertical-align: middle;" /></a> for every prime <a href="javascript:;" onclick="do_texpopup('p', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/83878c91171338902e0fe0fb97a8c47a-1.gif" alt="p" title="p" style="border: 0px; vertical-align: middle;" /></a>.<br />
<br />
I know <a href="javascript:;" onclick="do_texpopup('x^4 - x^2 + 1', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/77351f3c82b89e09953d491f1315a22a-1.gif" alt="x^4 - x^2 + 1" title="x^4 - x^2 + 1" style="border: 0px; vertical-align: middle;" /></a> is the 12th cyclotomic polynomial and know a few properties of such polynomials, but I'm not sure if that really helps here. I can also show that <a href="javascript:;" onclick="do_texpopup('p^2 -1', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/0642d2ecc495ba3703a4142af4720026-1.gif" alt="p^2 -1" title="p^2 -1" style="border: 0px; vertical-align: middle;" /></a> is divisible by 12 for <a href="javascript:;" onclick="do_texpopup('p&gt;3', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/4b61bac5579fca1e0aa08306f4e4c1ee-1.gif" alt="p&gt;3" title="p&gt;3" style="border: 0px; vertical-align: middle;" /></a> but can't seem to make use of that (although have been given a hint that this would be useful).</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>Boysilver</dc:creator>
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			<title>Not a power of 2</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115407-not-power-2-a.html</link>
			<pubDate>Wed, 18 Nov 2009 20:32:50 GMT</pubDate>
			<description><![CDATA[Show that k^n+k^{n-1}+\ldots +k+1 can't be a power of 2 if k>1 (n,k\in\mathbb{Z^+}).]]></description>
			<content:encoded><![CDATA[<div>Show that <a href="javascript:;" onclick="do_texpopup('k^n+k^{n-1}+\\ldots +k+1', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/702fa4b184971d92a52de021cca16257-1.gif" alt="k^n+k^{n-1}+\ldots +k+1" title="k^n+k^{n-1}+\ldots +k+1" style="border: 0px; vertical-align: middle;" /></a> can't be a power of 2 if <a href="javascript:;" onclick="do_texpopup('k&gt;1', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/d37c0d918e9117937016dc3dd13c2faa-1.gif" alt="k&gt;1" title="k&gt;1" style="border: 0px; vertical-align: middle;" /></a> (<a href="javascript:;" onclick="do_texpopup('n,k\\in\\mathbb{Z^+}', 'math'); return false;"><img src="http://www.mathhelpforum.com/math-help/latex2/img/ce56cee84d0abb413bfdf6137511fe7f-1.gif" alt="n,k\in\mathbb{Z^+}" title="n,k\in\mathbb{Z^+}" style="border: 0px; vertical-align: middle;" /></a>).</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>james_bond</dc:creator>
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			<title>prove irrational</title>
			<link>http://www.mathhelpforum.com/math-help/number-theory/115394-prove-irrational.html</link>
			<pubDate>Wed, 18 Nov 2009 19:22:40 GMT</pubDate>
			<description>prove that sin(1) (one radian) is irrational. 
Hint start with taylor series expansion</description>
			<content:encoded><![CDATA[<div>prove that sin(1) (one radian) is irrational.<br />
Hint start with taylor series expansion</div>

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			<category domain="http://www.mathhelpforum.com/math-help/number-theory/">Number theory</category>
			<dc:creator>scubasteve123</dc:creator>
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