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Old November 4th, 2009, 05:43 AM
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Default Length of a vector

Hi Math help Forum

I'm not sure if this is the right thread to be posting this in, so sorry.

the question is to calculate |a x b| where

a= i+j-k
b=2i-j+3k

I've worked out a x b to be 2i - 5j - 3k , but I'm not really sure as to where to go from here.

any help would be great

Thanks

ES
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Old November 4th, 2009, 06:04 AM
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Originally Posted by El Sparko View Post
Hi Math help Forum

I'm not sure if this is the right thread to be posting this in, so sorry.

the question is to calculate |a x b| where

a= i+j-k
b=2i-j+3k

I've worked out a x b to be 2i - 5j - 3k , but I'm not really sure as to where to go from here.

any help would be great

Thanks

ES
Calculate now the length (or the absolute value) of (2, -5, -3).

You should get the result |\vec v| = \sqrt{38}
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