Math Help Forum

Math Help Forum Feed Site Feed

Go Back   Math Help Forum > Pre-University Math Help > Geometry
Reply
 
Thread Tools Display Modes
  #1  
Old November 21st, 2009, 10:04 AM
Newbie
 
Join Date: Nov 2009
Posts: 3
Thanks: 3
Thanked 0 Times in 0 Posts
cvhubb is on a distinguished road
Default How to find the length of the hypotenuse

Hi,

Sorry if this a easy problem.... I've been out of school now for 15 years and trying to study up on taking the ACT test to start college in August. There is so much I have forgotten. I could use some help with this problem. Incase you cannot read the question it says....

In the isosceles right triangle below, AB = 10 feet. What is the length, in feet, of AC ?

It has a multiple choice and I'm thinking the answer is E (I believe that this is what my brother said) but I need to know the steps of how he got that for the answer.



Thanks a bunch for your help

Veronica
Reply With Quote
Advertisement
 
  #2  
Old November 21st, 2009, 10:10 AM
skeeter's Avatar
MHF Contributor

 
Join Date: Jun 2008
Location: North Texas
Posts: 6,101
Country:
Thanks: 51
Thanked 2,628 Times in 2,481 Posts
skeeter has a reputation beyond reputeskeeter has a reputation beyond reputeskeeter has a reputation beyond reputeskeeter has a reputation beyond reputeskeeter has a reputation beyond reputeskeeter has a reputation beyond reputeskeeter has a reputation beyond reputeskeeter has a reputation beyond reputeskeeter has a reputation beyond reputeskeeter has a reputation beyond reputeskeeter has a reputation beyond repute
Default

Geometry: Special Right Triangles - CliffsNotes
Reply With Quote
The following users thank skeeter for this useful post:
Donate to MHF
  #3  
Old November 21st, 2009, 10:12 AM
Member
 
Join Date: Mar 2008
Posts: 177
Country:
Thanks: 34
Thanked 38 Times in 36 Posts
Unenlightened is on a distinguished road
Default

Quote:
Originally Posted by cvhubb View Post
Hi,

Sorry if this a easy problem.... I've been out of school now for 15 years and trying to study up on taking the ACT test to start college in August. There is so much I have forgotten. I could use some help with this problem. Incase you cannot read the question it says....

In the isosceles right triangle below, AB = 10 feet. What is the length, in feet, of AC ?

It has a multiple choice and I'm thinking the answer is E (I believe that this is what my brother said) but I need to know the steps of how he got that for the answer.



Thanks a bunch for your help

Veronica

Note the isoceles, which means two of the sides of the triangle are of the same length.
Then I suggest you look at the wikipedia page for "Pythagoras' theorem" which will explain the formula for getting the length of the hypotenuse of a right-angled triangle. (You can tell the triangle is a right-angled one because of the little square drawn in the corner beside the B. If that weren't there, you could not assume the triangle was right-angled unless stated.)

edit: actually it does say in the question that the triangle is right-angled, apologies..
Reply With Quote
The following users thank Unenlightened for this useful post:
Donate to MHF
  #4  
Old November 21st, 2009, 10:32 AM
Newbie
 
Join Date: Nov 2009
Posts: 3
Thanks: 3
Thanked 0 Times in 0 Posts
cvhubb is on a distinguished road
Default

Quote:
Originally Posted by skeeter View Post
Thanks skeeter for the link. A lot of good info to help me out. Going now to read some more.

Quote:
Originally Posted by Unenlightened View Post
Note the isoceles, which means two of the sides of the triangle are of the same length.
Then I suggest you look at the wikipedia page for "Pythagoras' theorem" which will explain the formula for getting the length of the hypotenuse of a right-angled triangle. (You can tell the triangle is a right-angled one because of the little square drawn in the corner beside the B. If that weren't there, you could not assume the triangle was right-angled unless stated.)

edit: actually it does say in the question that the triangle is right-angled, apologies..
Thank you too Unenlightened... that is what I thought since it was a right triangle that AB and BC would be the same length, both would be 10. So the forumula I need to use is c = square root of a^2 + b^ , right? When I put this into my calculator I get 14.14213562 . Which I know letter E in the multiple choice is the answer.

One question I have a TI-30X IIS calculator.... is there some way you can change that number to a square root or will I just have to enter in the multiple choice to see which one is right?

Thanks Again,
Veronica
Reply With Quote
  #5  
Old November 21st, 2009, 11:21 AM
Member
 
Join Date: Mar 2008
Posts: 177
Country:
Thanks: 34
Thanked 38 Times in 36 Posts
Unenlightened is on a distinguished road
Default

Quote:
Originally Posted by cvhubb View Post
Thanks skeeter for the link. A lot of good info to help me out. Going now to read some more.



Thank you too Unenlightened... that is what I thought since it was a right triangle that AB and BC would be the same length, both would be 10. So the forumula I need to use is c = square root of a^2 + b^ , right? When I put this into my calculator I get 14.14213562 . Which I know letter E in the multiple choice is the answer.

One question I have a TI-30X IIS calculator.... is there some way you can change that number to a square root or will I just have to enter in the multiple choice to see which one is right?

Thanks Again,
Veronica
If you leave it as a square root instead of using the calculator, it's probably easier..
ie. (AC)^{2} = (AB)^2+(BC)^{2}
so (AC)^{2}= 100 + 100
(AC)^{2}= 200
AC = \sqrt{200}
AC= \sqrt{100}\sqrt{2}
AC=10\sqrt{2}
Reply With Quote
The following users thank Unenlightened for this useful post:
Donate to MHF
  #6  
Old November 21st, 2009, 11:25 AM
Newbie
 
Join Date: Nov 2009
Posts: 3
Thanks: 3
Thanked 0 Times in 0 Posts
cvhubb is on a distinguished road
Default

Quote:
Originally Posted by Unenlightened View Post
If you leave it as a square root instead of using the calculator, it's probably easier..
ie. (AC)^{2} = (AB)^2+(BC)^{2}
so (AC)^{2}= 100 + 100
(AC)^{2}= 200
AC = \sqrt{200}
AC= \sqrt{100}\sqrt{2}
AC=10\sqrt{2}
OK, gottcha and thanks a bunch
Reply With Quote
Reply

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off
Forum Jump


All times are GMT -7. The time now is 02:45 AM.


Powered by vBulletin® Version 3.7.3
Copyright ©2000 - 2010, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.2.0 ©2008, Crawlability, Inc.
©2005 - 2009 Math Help Forum


Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.