| 
November 21st, 2009, 10:04 AM
| | Newbie | | Join Date: Nov 2009
Posts: 3
Thanks: 3
Thanked 0 Times in 0 Posts
| | How to find the length of the hypotenuse Hi,
Sorry if this a easy problem.... I've been out of school now for 15 years and trying to study up on taking the ACT test to start college in August. There is so much I have forgotten. I could use some help with this problem. Incase you cannot read the question it says....
In the isosceles right triangle below, AB = 10 feet. What is the length, in feet, of AC ?
It has a multiple choice and I'm thinking the answer is E (I believe that this is what my brother said) but I need to know the steps of how he got that for the answer.
Thanks a bunch for your help
Veronica | 
November 21st, 2009, 10:10 AM
|  | MHF Contributor | | Join Date: Jun 2008 Location: North Texas
Posts: 6,101
Country: Thanks: 51
Thanked 2,628 Times in 2,481 Posts
| | | | The following users thank skeeter for this useful post: | |  | 
November 21st, 2009, 10:12 AM
| | Member | | Join Date: Mar 2008
Posts: 177
Country: Thanks: 34
Thanked 38 Times in 36 Posts
| | Quote:
Originally Posted by cvhubb Hi,
Sorry if this a easy problem.... I've been out of school now for 15 years and trying to study up on taking the ACT test to start college in August. There is so much I have forgotten. I could use some help with this problem. Incase you cannot read the question it says....
In the isosceles right triangle below, AB = 10 feet. What is the length, in feet, of AC ?
It has a multiple choice and I'm thinking the answer is E (I believe that this is what my brother said) but I need to know the steps of how he got that for the answer.
Thanks a bunch for your help
Veronica |
Note the isoceles, which means two of the sides of the triangle are of the same length.
Then I suggest you look at the wikipedia page for "Pythagoras' theorem" which will explain the formula for getting the length of the hypotenuse of a right-angled triangle. (You can tell the triangle is a right-angled one because of the little square drawn in the corner beside the B. If that weren't there, you could not assume the triangle was right-angled unless stated.)
edit: actually it does say in the question that the triangle is right-angled, apologies.. | | The following users thank Unenlightened for this useful post: | |  | 
November 21st, 2009, 10:32 AM
| | Newbie | | Join Date: Nov 2009
Posts: 3
Thanks: 3
Thanked 0 Times in 0 Posts
| | Quote:
Originally Posted by skeeter | Thanks skeeter for the link. A lot of good info to help me out. Going now to read some more. Quote:
Originally Posted by Unenlightened Note the isoceles, which means two of the sides of the triangle are of the same length.
Then I suggest you look at the wikipedia page for "Pythagoras' theorem" which will explain the formula for getting the length of the hypotenuse of a right-angled triangle. (You can tell the triangle is a right-angled one because of the little square drawn in the corner beside the B. If that weren't there, you could not assume the triangle was right-angled unless stated.)
edit: actually it does say in the question that the triangle is right-angled, apologies.. | Thank you too Unenlightened... that is what I thought since it was a right triangle that AB and BC would be the same length, both would be 10. So the forumula I need to use is c = square root of a^2 + b^ , right? When I put this into my calculator I get 14.14213562 . Which I know letter E in the multiple choice is the answer.
One question I have a TI-30X IIS calculator.... is there some way you can change that number to a square root or will I just have to enter in the multiple choice to see which one is right?
Thanks Again,
Veronica | 
November 21st, 2009, 11:21 AM
| | Member | | Join Date: Mar 2008
Posts: 177
Country: Thanks: 34
Thanked 38 Times in 36 Posts
| | Quote:
Originally Posted by cvhubb Thanks skeeter for the link. A lot of good info to help me out. Going now to read some more.
Thank you too Unenlightened... that is what I thought since it was a right triangle that AB and BC would be the same length, both would be 10. So the forumula I need to use is c = square root of a^2 + b^ , right? When I put this into my calculator I get 14.14213562 . Which I know letter E in the multiple choice is the answer.
One question I have a TI-30X IIS calculator.... is there some way you can change that number to a square root or will I just have to enter in the multiple choice to see which one is right?
Thanks Again,
Veronica | If you leave it as a square root instead of using the calculator, it's probably easier..
ie. (AC)^{2} = (AB)^2+(BC)^{2}
so (AC)^{2}= 100 + 100
(AC)^{2}= 200
AC = 
AC= 
AC= | | The following users thank Unenlightened for this useful post: | |  | 
November 21st, 2009, 11:25 AM
| | Newbie | | Join Date: Nov 2009
Posts: 3
Thanks: 3
Thanked 0 Times in 0 Posts
| | Quote:
Originally Posted by Unenlightened If you leave it as a square root instead of using the calculator, it's probably easier..
ie. (AC)^{2} = (AB)^2+(BC)^{2}
so (AC)^{2}= 100 + 100
(AC)^{2}= 200
AC = 
AC= 
AC=  | OK, gottcha and thanks a bunch | | Thread Tools | | | | Display Modes | Linear Mode |
Posting Rules
| You may not post new threads You may not post replies You may not post attachments You may not edit your posts HTML code is Off | | | All times are GMT -7. The time now is 02:45 AM. | | |
 | |  |