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Old 06-10-2008, 09:37 PM
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Default Please assist me in creating a Fibonacci Parallelogram

Hi all,

Again I am off on a project of my own related to design work I am doing.

Please move if this is the wrong forum for this question - I suspect it is not really College Level geometry (well I certainly am not ;-) )

Basically I want to reproduce a figure that I have grabbed a 3D render of. I need to do it in a vector drawing programme and need to know how to derive the angles and lengths of the sides.

The form is that of the three intersecting golden rectangles rotated in such a way as to produce the appearance of three intersecting planes that fit within a 3 Dimensional Icosahedron.

I reproduce the figures I am working from here:




In tracing the rasterised vector artwork above I find that the sides of the parallelograms are about 6.5 and 10.5 cm. When I use trig to find the top right apex interior angle it is 59.4° - or I assume 60° due to the perspective method used...

Is it the case that the matter of creating a parallelogram out of a golden rectangle does not in fact interfere with the properties of the object?

I figure that all I need to work out is how to take a golden rectancle and shear it in such a way that it is still a fibonacci shape...

I am working off the basis of a golden rectangle in the simplest way I can:

10cm x 16.18cm

Is this possible or is the very nature of shearing the golden rectangle to create the illusion of 3 Dimensions going to destroy the phi relationships - and if so can I just pick a suitable interior angle and then rotate three copies of the created parallelogram in such a way as to get the effect...

I will be then using colour and transparency blending to create a geometric logo/design element in stereo...

Many thanks in advance to anybody who can provide any (ph)insight
Regards,
Will

[update]
these are the constructs I have managed this afternoon using only very elementary assumptions about the geometries involved...

[/update]

Last edited by stardotstar; 06-11-2008 at 01:19 AM. Reason: update
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Old 06-15-2008, 10:40 PM
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Default Solved

I have found a solution to this - the construction of a golden parallelogram is from the pentogram enclosed in a pentagon.

It has the special property of the shorter diagonal being equal to the longer parappel sides and the ratio of the short to long sides being Phi.

I am continuing to pursue this design and will post more if I come up with anything of note.

\\'
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