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Old 09-03-2008, 03:46 PM
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Exclamation Geometry help please

trying to find distance between 2 pts. using distance formula of
(1,4) (5,1)
I can get to the end of the problem, but the book says I'm wrong...

The answer I'm getting is the square root of 45, but the book says the answer is 3 times the square root of five.

due tommorow for school

Please tell me what I'm doing wrong.

thanks
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Old 09-03-2008, 03:49 PM
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But they're the same thing: \sqrt{45} \ = \ \sqrt{9 \cdot 5} \ = \ \sqrt{9}\cdot \sqrt{5} \ =  \ 3\sqrt{5}
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\int_0^{\infty} \prod_{n = 1}^{\infty} \left( \frac{1 + \left(\frac{x}{b+n}\right)^2}{1+  \left(\frac{x}{a + n - 1}\right)^2}\right) dx = \frac{\sqrt{\pi}}{2} \ \frac{\Gamma \! \left(a + \frac{1}{2}\right)}{\Gamma (a)} \ \frac{\Gamma (b+1)}{\Gamma \! \left(b + \frac{1}{2}\right)} \ \frac{\Gamma \! \left(b-a+\frac{1}{2}\right)}{\Gamma (b-a+1)}
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Old 09-04-2008, 01:49 PM
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Default geometry help

posted by dear john

if the two points you listed are correct i.e. 1,4 and 5.1 the answer is 5
distance between the points

bj
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