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Old 11-06-2008, 06:08 PM
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Default area, perimeter and units

if we have a circle with perimeter 30 cm, how many cm^2(exactly) are in the circle area? in other words, how many square units(cm^2)(but exactly) are there, if i were count them?
Thanks for your supports and sorry for my languages...
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Old 11-06-2008, 07:00 PM
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2\pi r = 30 \Leftrightarrow r = \frac{{30}}{{2\pi }} \Rightarrow A_ \odot   = \pi \left( {\frac{{30}}{{2\pi }}} \right)^2
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Old 11-07-2008, 11:37 AM
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Quote:
Originally Posted by Nacho View Post
2\pi r = 30 \Leftrightarrow r = \frac{{30}}{{2\pi }} \Rightarrow A_ \odot   = \pi \left( {\frac{{30}}{{2\pi }}} \right)^2
thanks but u calculate circle area. i want to count only exact square units(not semi-square or another) in the circle area...i hope i can explain the problem correctly....
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Old 11-07-2008, 12:07 PM
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Quote:
Originally Posted by turkmath View Post
thanks but u calculate circle area. i want to count only exact square units(not semi-square or another) in the circle area...i hope i can explain the problem correctly....
Do you mean how many actual squares, 1 cm on a side, can be put into the circle without overlapping?
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Old 11-07-2008, 12:20 PM
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Quote:
Originally Posted by HallsofIvy View Post
Do you mean how many actual squares, 1 cm on a side, can be put into the circle without overlapping?
totally yes, yes...this is true question and good meaning...
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Old 11-08-2008, 01:20 PM
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is it complicate or advanced question?

Last edited by turkmath; 11-11-2008 at 05:21 PM. Reason: true sentence
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Old 11-11-2008, 05:22 PM
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pls help, thanks for your supports...
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Old 11-23-2008, 04:58 PM
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it is still unsolved... Can i use any math software for solving this problem?Thanks for your comments...
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