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Old November 9th, 2008, 07:01 PM
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Default Triangle Proof

Could anyone help me with this 3D figure proof?



I don't care if its a paragraph proof, a flow proof, or a 2 column proof, whatever floats your boat =D

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Old November 9th, 2008, 08:20 PM
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Could anyone help me with this 3D figure proof?



You also know that QC is shared by both triangles so that QC =QC.
Therefore, you can conclude side angle side.
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Old November 9th, 2008, 08:39 PM
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Hello, disturbedpanda!

Quote:



\begin{array}{cccc}
1. & CR = CS & & \text{Given} \\
2. & QC \perp CR & & \text{Given} \\
3. & QC \perp CS & & \text{Given} \\
4. & \angle QCR = \angle QCS & & \text{d{e}f. of perp.} \\
5. & QC = QC & & \text{Identity} \\
6.& \Delta QCR \cong \Delta QCS & & \text{s.a.s.}\end{array}

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