triangle

sadieann · #1 $Old$ 11-10-2008, 05:08 PM

Find the area of a triangle with sides of length a = 5 and b = 25 and angle B= 14 degrees.

Find the area of a triangle with sides of length a = 14 and b = 20 and angle A = 13 degrees.

2976math · #2 $Old$ 11-10-2008, 05:25 PM

Quote:

Originally Posted by sadieann $View Post$

Find the area of a triangle with sides of length a = 5 and b = 25 and angle B= 14 degrees.

Find the area of a triangle with sides of length a = 14 and b = 20 and angle A = 13 degrees.

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Sadieann,
1st use formula c^2=a^2 + b^2 - 2ab CosC to find length c
2nd once you know all 3 sides a,b,c then use formula
A=Square root of [ s (s-a) * (s-b)* (s-c) ]
where s = (a+b+c)/2
for 1st question. c = 20.18, s =25.09, area = 14.92 square unit.

you do the 2nd question