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Old 11-10-2008, 10:39 PM
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Default How many different ordered pairs?

Draw y = x^2 + 2x -3 on the interval [-4, 2]. On the same xy-plane, draw (x + 1)^2 + (y + 4)^2 = 16. How many different ordered pairs satisfy both graphed equations?
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  #2  
Old 11-10-2008, 10:52 PM
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Originally Posted by magentarita View Post
Draw y = x^2 + 2x -3 on the interval [-4, 2]. On the same xy-plane, draw (x + 1)^2 + (y + 4)^2 = 16. How many different ordered pairs satisfy both graphed equations?
You should have enough info now to answer the question:



--Chris
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\color{blue}\text{ if }\Re[z]<0\text{ and }0<a\leq 1,

\color{blue}\zeta(z,a)=\frac{2\Gamma(1-z)}{(2\pi)^{1-z}}\left[\sin\left(\frac{\pi z}{2}\right)\sum_{n=1}^{\infty}\frac{\cos(2\pi a n)}{n^{1-z}}+\cos\left(\frac{\pi z}{2}\right)\sum_{n=1}^{\infty}\frac{\sin(2\pi a n)}{n^{1-z}}\right]
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Old 11-11-2008, 11:05 PM
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Originally Posted by Chris L T521 View Post
You should have enough info now to answer the question:



--Chris
Is the answer two points?
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Old 11-11-2008, 11:58 PM
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Is the answer two points?
Yes. There are two points [ordered pairs].

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\color{blue}\text{ if }\Re[z]<0\text{ and }0<a\leq 1,

\color{blue}\zeta(z,a)=\frac{2\Gamma(1-z)}{(2\pi)^{1-z}}\left[\sin\left(\frac{\pi z}{2}\right)\sum_{n=1}^{\infty}\frac{\cos(2\pi a n)}{n^{1-z}}+\cos\left(\frac{\pi z}{2}\right)\sum_{n=1}^{\infty}\frac{\sin(2\pi a n)}{n^{1-z}}\right]
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Old 11-12-2008, 06:37 PM
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Default ok........

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Yes. There are two points [ordered pairs].

--Chris
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