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Old December 4th, 2008, 07:11 AM
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Default Show that the equation to its locus is...?

A point moves so that the distance between the feet of the perpendiculars from it on the pair of non parallel straight lines given by bx^2 + 2hxy + by^2 = 0 is a constant 2 units. Show that the equation to its locus is x^2 + y^2 = 4h^2/(h^2 - b^2)

I tried to solve it but each time, I ended up with an equation which was not a circle. Can anyone help?


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