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#1

$Old$ 08-11-2008, 08:20 AM

OPETH $OPETH is offline$

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$Default$ 2. question

a and b are positive integers,

$3a-7b=10$

and if $b<12$

How different values of the b available ?

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$Old$ 08-11-2008, 08:36 AM

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Originally Posted by OPETH $View Post$

a and b are positive integers,

$3a-7b=10$

and if $b<12$

How different values of the b available ?

You can do this yourself, just test what happens when $b=0$ and $b=1$ and $b=2$ and $b=3$ and so on until you get to $b=11$

Then just count up how many times $a$ came out to be a positive integer.

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$Old$ 08-11-2008, 08:38 AM

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$3a=10+7b$

Yeah! I solved the question.

Answer:4

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#4

$Old$ 10-01-2008, 09:21 AM

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3a=10+7b
b>0
since with any b ,a will be positive in this case,that match the criteria
so be can be 0=<b<12
and with b=11 a=29
ad with b=0 a=10/3
so 10/3=<a<=29

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