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Old 11-02-2008, 01:10 AM
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Default need help:

x^2-2^x+1=0


find no. of values of x which satisfies the equation
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Old 11-02-2008, 01:25 AM
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Originally Posted by great_math View Post
x^2-2^x+1=0


find no. of values of x which satisfies the equation
Try drawing the graphs of y = x^2 + 1 and y = 2^x and examining how many intersection points there are.
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