Math Help Forum

Math Help Forum Feed Site Feed

Go Back   Math Help Forum > Math Resources > LaTex Help
Reply
 
Thread Tools Display Modes
  #1  
Old September 30th, 2009, 06:39 PM
Senior Member
 
Join Date: Jul 2006
Location: Shabu City
Posts: 381
Country:
Thanks: 440
Thanked 13 Times in 13 Posts
^_^Engineer_Adam^_^ is on a distinguished road
Default test

\sqrt[n]{\frac{a}{b}}\:\:=\:\:\frac{ {\sqrt[n]{a}} {\sqrt[n]{b}}   }\;\;\mbox{such that a and b}>\:0\:
Reply With Quote
Advertisement
 
  #2  
Old September 30th, 2009, 09:59 PM
Super Member

 
Join Date: May 2006
Location: Lexington, MA (USA)
Posts: 7,286
Thanks: 555
Thanked 4,649 Times in 3,712 Posts
Soroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond repute
Default

Hello, ^_^Engineer_Adam^_^

You have too many braces . . .


You typed:

[math ] \sqrt[n]{\frac{a}{b}}\:\:=\:\:\frac{ {\sqrt[n]{a}} {\sqrt[n]{b}} }\;\;\mbox{such that a and b}>\:0\:[/math]


and produced this:

\sqrt[n]{\frac{a}{b}}\:\:=\:\:\frac{ {\sqrt[n]{a}} {\sqrt[n]{b}}   }\;\;\mbox{such that a and b}>\:0\:



Eliminate the red braces above:

[math ] \sqrt[n]{\frac{a}{b}}\:\:=\:\:\frac {\sqrt[n]{a}} {\sqrt[n]{b}}\;\;\mbox{such that a and b}>\:0\:[/math]


which produces:

\sqrt[n]{\frac{a}{b}}\:\:=\:\:\frac {\sqrt[n]{a}} {\sqrt[n]{b}} \;\;\mbox{such that a and b}>\:0\:

Reply With Quote
  #3  
Old October 8th, 2009, 03:54 PM
Junior Member
 
Join Date: Sep 2009
Posts: 31
Country:
Thanks: 0
Thanked 0 Times in 0 Posts
Madspeter is on a distinguished road
Default just another test

[math]j-i > 2^n \rightarrow A(i,j) \leq n[\math]


[math]x^2\sqrt{x}[\math]
Reply With Quote
  #4  
Old October 9th, 2009, 06:49 AM
Super Member

 
Join Date: May 2006
Location: Lexington, MA (USA)
Posts: 7,286
Thanks: 555
Thanked 4,649 Times in 3,712 Posts
Soroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond reputeSoroban has a reputation beyond repute
Default

Hello, Madspeter!

Quote:
[math]j-i > 2^n \rightarrow A(i,j) \leq n[\math]

[math]x^2\sqrt{x}[\math]

You must close LaTeX with: .[/math]


Then you will get:

j-i > 2^n \rightarrow A(i,j) \leq n

x^2\sqrt{x}

Reply With Quote
  #5  
Old October 9th, 2009, 03:23 PM
Junior Member
 
Join Date: Sep 2009
Posts: 31
Country:
Thanks: 0
Thanked 0 Times in 0 Posts
Madspeter is on a distinguished road
Default

thanks a lot. )
Reply With Quote
Reply

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off
Forum Jump


All times are GMT -7. The time now is 09:54 PM.


Powered by vBulletin® Version 3.7.3
Copyright ©2000 - 2009, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.2.0 ©2008, Crawlability, Inc.
©2005 - 2009 Math Help Forum


Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.