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Old October 15th, 2009, 04:15 PM
RRH RRH is offline
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Only took me 45 minutes to type this up .... not setting any records here :P







Please try using Stapel sources before using my results. I am trying to practice using latex and it took me approx 45 minutes to type this up (yes I am slow) and I do not want to lose my work; therefore, I am going to post it, but you should try to do the work yourself first.

Vertex = (\frac{3}{4} , \frac{49}{8})

x-int = -1 and \frac{5}{2}

y-int = 5

domain is (-inf,+inf)

range is (-inf, \frac{49}{8}]

See explanation below to determine how I came to these results.

Completing the Square

f(x) = -2x^2+3x+5

When completing the square the value of "a" should not be any number other than 1; therefore, factor out the -2

-2(x^2-\frac{3}{2}x)+5

Now divide -\frac{3}{2} by 2 and square the result. The equation should now look like this.

-2(x^2-\frac{3}{2}x+\frac{9}{16}-\frac{9}{16})+5

To move the -\frac {9}{16}out of the parenthesis you have to multiply it by -2

-2(x^2-\frac{3}{2}x+\frac{9}{16})+5+\frac{9}{8}

Factor within the parenthesis and clean up outside the parenthesis. The vector format of your function should look like below

-2(x-\frac{3}{4})^2+\frac{49}{8}

To determine the y-int take the original function f(x) = -2x^2+3x+5 substitute 0 for x and you should get the y-int of 5

To get the x-int take the vertex format of the function -2(x-\frac{3}{4})^2+\frac{49}{8} and substitute 0 for y

-2(x-\frac{3}{4})^2+\frac{49}{8}=0

-2(x-\frac{3}{4})^2=-\frac{49}{8}

Divide both sides by -2

(x-\frac{3}{4})^2=\frac{49}{16}

\sqrt(x-\frac{3}{4})^2=\sqrt\frac{49}{16}

x-\frac{3}{4}=\pm\frac{7}{4}

x=\frac{3}{4}\pm\frac{7}{4}

the x-int = -1 , \frac{5}{2}

Last edited by RRH; October 15th, 2009 at 05:16 PM.
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Old October 15th, 2009, 04:16 PM
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f(x) = -2x^2+3x+5

-2(x^2-\frac{3}{2}x)+5
well done
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Old October 16th, 2009, 07:50 AM
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Quote:
Originally Posted by RRH View Post
...

Vertex = (\frac{3}{4} , \frac{49}{8})

...
I've modified the quoted line a little bit:

Vertex = \left( \frac{3}{4} , \frac{49}{8} \right)

Click on the formula above to see the code.
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Old October 16th, 2009, 09:07 AM
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[math]\left( \frac{3}{4} , \frac{49}{8} \right)[/math] gives \left( \frac{3}{4} , \frac{49}{8} \right)
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Old October 16th, 2009, 01:16 PM
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While \frac{1}{2} produces: .\frac{1}{2}

. . we can make smaller fractions with \tfrac{1}{2}: .\tfrac{1}{2}



\frac{\frac{x}{2}}{\frac{y}{3}} produces: .\frac{\frac{x}{2}}{\frac{y}{3}}

But we can make larger fractions with \dfrac:
. . \frac{\dfrac{x}{2}}{\dfrac{y}{3}} produces: .\frac{\dfrac{x}{2}}{\dfrac{y}{3}}

Also use \infty for: .\infty

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