Triple lower limits in summation sign (urgent)

Jodles · #1 $Old$ October 30th, 2009, 04:11 AM

Hi!

How do I get several limits below each other using the summation sign? I.e. $\sum\limits_{i \neq j} A_{ij}$ , but I would also like $i, j \neq r, s$ and $i, j \neq s, r$ on two lines below the first limit...

Thanks!

CaptainBlack · #2 $Old$ October 30th, 2009, 05:24 AM

Quote:

Originally Posted by Jodles $View Post$

Hi!

How do I get several limits below each other using the summation sign? I.e. $\sum\limits_{i \neq j} A_{ij}$ , but I would also like $i, j \neq r, s$ and $i, j \neq s, r$ on two lines below the first limit...

Thanks!

[math]\sum_
{ \tiny \begin{array}{c} x>1 \\ y<8\\ u \in A \end{array} }
x+y+u[/math]

gives:

$\sum_{ \tiny \begin{array}{c} x>1 \\ y<8\\ u \in A \end{array} } x+y+u$

flyingsquirrel · #3 $Old$ October 31st, 2009, 02:27 AM

Quote:

Originally Posted by Jodles $View Post$

How do I get several limits below each other using the summation sign? I.e. $\sum\limits_{i \neq j} A_{ij}$ , but I would also like $i, j \neq r, s$ and $i, j \neq s, r$ on two lines below the first limit...

[math]\sum_{\substack{i \neq j\\ i, j \neq r, s\\ i, j \neq s, r}} A_{ij}[/math] gives

$\sum_{\substack{i \neq j\\ i, j \neq r, s\\ i, j \neq s, r}} A_{ij}$