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July 13th, 2007, 12:03 PM
|  | Rapscallion | | Join Date: Mar 2005 Location: San Diego
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| | Quote:
Originally Posted by Krizalid
Are you gonna install the Cancel Package MG? | What is the cancel package?
__________________ Math Guru | 
July 13th, 2007, 12:22 PM
|  | Math Engineering Student | | Join Date: Mar 2007 Location: Santiago
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| | Quote:
Originally Posted by ThePerfectHacker Krizalid do you know how to make a double contour integral? | Nope, I just saw it somewhere and really looks cool  Quote:
Originally Posted by ThePerfectHacker This is how Captain Blank does it, Code: \skew{57} {\skew{15}\subset \supset} \iint \mbox{ }
The old command was either \ooint or \oiint
But they do not work now.
What command did you use to create your avatar on AoPs? | You can use \mathop{{\int\!\!\!\!\!\int}\mkern-21mu\bigcirc}{}
This yields Quote:
Originally Posted by MathGuru What is the cancel package? | I mean | | The following users thank Krizalid for this useful post: | |  | 
July 13th, 2007, 04:02 PM
|  | MHF Contributor | | Join Date: Jun 2007 Location: Medgidia, Romania
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| | How can I insert an image in my post?
I used the "Insert image " button, but one ask me to introduce the URL and the image is in my own computer. | 
July 13th, 2007, 04:05 PM
|  | Math Engineering Student | | Join Date: Mar 2007 Location: Santiago
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| | You can use ImageShack
It's the best way to upload & plug the images to the forum  | | The following users thank Krizalid for this useful post: | |  | 
July 13th, 2007, 05:42 PM
|  | Eater of Worlds | | Join Date: Jul 2006 Location: Chaneysville, PA
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| | Quote:
Originally Posted by red_dog How can I insert an image in my post?
I used the "Insert image " button, but one ask me to introduce the URL and the image is in my own computer. |
I've never used Image Shack on this site. I always upload from my computer. Go to "manage attachments", then click on browse at "upload file from your computer". It's always worked great for me. | 
July 13th, 2007, 05:58 PM
|  | MHF Contributor | | Join Date: Jun 2007 Location: Medgidia, Romania
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| | But I don't find "Manage attachments". | 
July 13th, 2007, 06:23 PM
|  | Eater of Worlds | | Join Date: Jul 2006 Location: Chaneysville, PA
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| | Really?. That's odd. It's there when I click "post reply". Scroll down to it. That doesn't make sense.
It's right beneath where you write your post. Under "Additional Options", "Attach Files". There's a icon bar that reads "Manage Attachmants". | | The following users thank galactus for this useful post: | |  | 
July 29th, 2007, 04:43 PM
|  | Global Moderator | | Join Date: Nov 2005 Location: New York City
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| | Is it possible to create the command To produce  .
Instead of writing, And hence saving time?
I have more such commands which I end up using. So if it possible I can create a list. | 
July 29th, 2007, 04:47 PM
|  | Math Engineering Student | | Join Date: Mar 2007 Location: Santiago
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| | I think it's possible to set a command like that.
You can also write in text using \text
Not hard.
P.S.: or for some special commands, using \mathrm | 
July 29th, 2007, 05:00 PM
|  | Senior Member | | Join Date: Mar 2007
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| | Is Texnic Center good for writing LaTeX files? | 
July 29th, 2007, 05:10 PM
|  | Math Engineering Student | | Join Date: Mar 2007 Location: Santiago
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| | Yeah, good software | 
July 29th, 2007, 05:27 PM
| | Senior Member | | Join Date: Apr 2006
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| | Quote:
Originally Posted by ThePerfectHacker Is it possible to create the command To produce  .
Instead of writing, And hence saving time?
I have more such commands which I end up using. So if it possible I can create a list. | The standard LaTeX method of creating commands does not work. Code: \newcommand{\gal}{\ensuremath{\mbox{Gal}}}
\gal
[LaTeX Error: Restricted command found (command)]
Last edited by ThePerfectHacker; July 29th, 2007 at 05:39 PM.
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July 31st, 2007, 11:18 PM
| | Newbie | | Join Date: Jul 2007
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| | Can someone please give me the code for:
1. 3^(3x +4).18^(-x-2)/24^(x+3).4^(-2x-1)
2. 21^(3x+1).7(2-x)/49^(x-1).27^(x-4)
Thanks in advance. | 
August 1st, 2007, 12:30 AM
|  | Grand Panjandrum | | Join Date: Nov 2005 Location: South of England
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| | Quote:
Originally Posted by Dean Can someone please give me the code for:
1. 3^(3x +4).18^(-x-2)/24^(x+3).4^(-2x-1)
2. 21^(3x+1).7(2-x)/49^(x-1).27^(x-4)
Thanks in advance. | 3^(3x +4).18^(-x-2)/24^(x+3).4^(-2x-1)
which is generated by:
[math]\frac{3^{3x +4}.18^{-x-2}}{24^{x+3}.4^{-2x-1}}[/math]
21^(3x+1).7(2-x)/49^(x-1).27^(x-4)
which is generated by:
[math]\frac{21^{3x+1}.7^{2-x}}{49^{x-1}.27^{x-4}}[/math]
RonL
__________________ Truth does not change because it is, or is not, believed by a majority of the people.
Giordano Bruno | | The following users thank CaptainBlack for this useful post: | |  | 
August 1st, 2007, 02:00 AM
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