Hi.....i'm stuck on the following question;

Show that no infinite soluble group has a composition series.


The hint for the question was to try by contradiction.

So i tried the following;

Suppose G is an infinite soluble group with a composition series.
G is soluble so all composition factors are cyclic and of prime order.

I think there will be a contradiction because G is infinite...but i just don't know

Thanks for your help

You almost have it: there's a (finite) series for G all of which factors are finite cyclic of prime order. But then, since a finite extension of a finite group is itself finite, we see G must be finite...(if is the cyclic series, then is finite, so is finite since are finite, etc...)

Tonio