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Old November 5th, 2009, 12:04 PM
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Default Bases and Linear Maps

Hi, Quick question:


If I know that T:V -> W is injective and B is a basis of V, how can i use that to show that T(B) is a basis of W?

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Old November 5th, 2009, 12:23 PM
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Originally Posted by dr4g0n9 View Post
Hi, Quick question:


If I know that T:V -> W is injective and B is a basis of V, how can i use that to show that T(B) is a basis of W?

Thanks

You can't because it isn't true: T: \mathbb{R}\rightarrow \mathbb{R}^2\,,\,\,T(r)=(r,0) is injective but not onto and thus no basis of the definition set can be mapped to a basis of the image set.

What is true is that if T is injective then the image of a basis is a lin. indep. set.

Tonio
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Old November 5th, 2009, 12:25 PM
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