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Old December 3rd, 2008, 05:23 PM
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Default is an ideal of a subring of a ring?

Hi,

I'm a little confused about ideals.

In our text an ideal is defined as:
For a ring R, an additive subgroup of ring were for each a\inA and ninN, a\dot n and n\dot a are both in N.

Is N necessarily a subring of R?

Thanks
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Old December 3rd, 2008, 05:42 PM
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Quote:
Originally Posted by ziggychick View Post
Is N necessarily a subring of R?
It depends how you define subrings. If you are a commutative algebraist then you usually think of rings as commutative unitary rings and subrings consist of 0 and 1 which are subsets and satisfy the properties of a ring under the induced operations. If you are a noncommutative algebraist then you usually think of rings are as general rings (which might or might not have unity) and define a subring to be a subset which satifies the properties of a ring under the induced operations. If you are a blondie then you define rings as what your boyfriend buys for you on Christmans (just joking if you happen to be a blonde ).

Under the more general definition ideals happen to be subrings, however, under the commutative algebraist definition ideals are not subrings unless they contain 1 (but in that case then they happen to be the entire ring themselves).
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Old December 3rd, 2008, 06:32 PM
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thanks. that was very helpful.

and i'm not a blondie but if i do get a ring for christmas i hope it commutes.
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