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Old December 15th, 2008, 11:10 AM
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Default Rings - Ideals - Equivalent statements?

I'm looking to prove that the following conditions are equivalent for an ideal I in a ring R.

1) 1 is in A
2) A contains a unit
3) A = R


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Old December 15th, 2008, 12:34 PM
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I guess that A means I

So since 1 is a unit, 1) \Rightarrow 2) is obvious.

If I contains a unit u, then, by ideal's definition, \forall a \in R, (au^{-1})u=a \in I, so R \subset I. I\subset R because of ideal's definition. So 2) \Rightarrow 3).

Finally, I=R \Rightarrow 1 \in R \subset I \Rightarrow 1\in I, therefore 3) \Rightarrow 1).
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