$Mathstud28 is a splendid one to behold$ $Mathstud28 is a splendid one to behold$ $Mathstud28 is a splendid one to behold$ $Mathstud28 is a splendid one to behold$ $Mathstud28 is a splendid one to behold$ $Mathstud28 is a splendid one to behold$ $Mathstud28 is a splendid one to behold$ $Mathstud28 is a splendid one to behold$

Mathstud28 $Mathstud28 is offline$

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Last Activity: January 26th, 2009 08:10 PM

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Showing Visitor Messages 1 to 10 of 28

$Chris L T521$
March 5th, 2009 11:55 PM
Chris L T521

Did you fall off the face of the Earth?!?
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$GaloisTheory1$

January 20th, 2009 10:17 PM
GaloisTheory1

Congrat's on your award!!
$Danny$
January 19th, 2009 05:13 PM
Danny

Alex, congrat's on your Galois Award. Well done!
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$Opalg$
January 13th, 2009 03:03 PM
Opalg

Congratulations to you too, Alex. You definitely deserved the award.
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$PaulRS$
January 13th, 2009 05:18 AM
PaulRS

Congratulations on your winning the Galois Award too
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$ADARSH$
January 13th, 2009 05:16 AM
ADARSH

Congrats Mathstud28 , you really deserved it
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$Mathstud28$

January 13th, 2009 12:51 AM
Mathstud28

Hmm...No reason in particular...I don't really know you very well...and I thought I would find out
$Moo$
January 13th, 2009 12:49 AM
Moo

And why were you wondering ?
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$Moo$
January 13th, 2009 12:46 AM
Moo

Yes, personnes âgées

Okay, in here, what looks like a B.Sc (I guess it's an equivalent) is done in 3 years. So I should be a sunior
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$Moo$
January 13th, 2009 12:39 AM
Moo

Hmmm I don't know what it is
I'm in 3rd year of college, and next year I'm going to enter a Masters (or an equivalent)
So am I a senior ? (in French, Senior designs people > 60 y.o. xD)
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About Me

About Mathstud28

Biography

I am an 18 year old aspiring mathematician

Location

Pennsylvania

Interests

Math, weightlifting, hedonistic ventures

Occupation

My job is keeping the Expo marker company afloat

Home Country

United States

Area of Interest

Analysis as well as integral and series compuation. Point-set and Geometric Topology and Diff Geo.
Signature
We're clever but we're clueless.

$\int_0^z\ln\Gamma(x+1)dx=\frac{z}{2}\ln(2\pi)-\frac{z(z+1)}{2}+z\ln\Gamma(z+1)$ $-\ln\left\{(2\pi)^{\frac{z}{2}}\exp\left(\frac{-z(z+1)}{2}-\frac{\gamma z^2}{2}\right)\prod_{k=1}^{\infty}\left\{\left(1+\frac{z}{k}\right)^k\exp\left(-z+\frac{z^2}{2k}\right)\right\}\right\}$

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Total Messages: 28
Most Recent Message: March 5th, 2009 11:55 PM
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General Information

Last Activity: January 26th, 2009 08:10 PM
Join Date: March 30th, 2008
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$Chris L T521$
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$NonCommAlg$
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$Opalg$
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$PaulRS$
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