What two-digit integer is six times the sum of its digits?

Solve this by setting up the equation:



where a and b are the number's two digits.

There's only a limited number of integral solutions, and you'll (probably) find that only one of those has both a and b in single digits.

Give it a play, see what happens.

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"No matter how fast or how far you run, you're still in the space where you are." -- Russell

If xy is the two digit number and x+y is the sum of the digits:

10x+y = (x+y)6
10x + y = 6x +6y
4x = 5y

Only two numbers satisify that