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October 26th, 2009, 12:56 AM
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| | conjugates of algebraic numbers hello,
i am having a problem with the following question:
Let $\alpha \in \mathbb{C}$ be an algebraic number of degree $d$ and denote by $\alpha^{(1)}, \ldots, \alpha^{(d)}$ the conjugates of $\alpha$.
a. Let $m = den(\alpha)$, ie the smallest positive integer $m \in \mathbb{Z}$ such that $m\alpha$ is an algebraic integer. Prove that $m^d \alpha^{(1)} \ldots \alpha^{(d)} \in \mathbb{Z}$.
b. Suppose that $\alpha \neq 0$. Prove that $|\alpha| \geq den(\alpha)^{-d} |\bar{\alpha}|^{1-d}$, where $\bar{\alpha}$ is the house of $\alpha$.
c. Using b. give a proof of the following inequality of Liouville (1844): Let $\alpha$ be an algebraic number in $\mathbb{R}$ of degree $d /geq 2$. Then there is a constant $c(\alpha) > 0$ such that $ |\alpha - p/q| \geq c(\alpha) q^{-d}$ for all $p, q \in \mathbb{Z}$ with $q>0$.
I thought I would write out the whole thing for clarity
Thank you
Last edited by zverik136; October 26th, 2009 at 12:56 AM.
Reason: latex rendering?
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October 26th, 2009, 03:56 AM
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| | Quote:
Originally Posted by zverik136 hello,
i am having a problem with the following question:
Let  be an algebraic number of degree d and denote by  the conjugates of  .
a. Let  , ie the smallest positive integer  such that  is an algebraic integer. Prove that  .
b. Suppose that  . Prove that  , where  is the house of  .
c. Using b. give a proof of the following inequality of Liouville (1844): Let  be an algebraic number in  of degree  . Then there is a constant  such that  for all  with  .
I thought I would write out the whole thing for clarity
Thank you | Hi there. I tried to correct your LaTex text as much as I could since in this site, unfortunately, to write properly in LaTex we have to open sentences with [math] and close them with [/math], instead of the well known and simpler $.
Nevertheless, as you can see, somethings still didn't come out nicely, as that thing "den(  )" and "d /geg2"
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October 26th, 2009, 07:19 PM
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| | Hello zverik!
Let  be the embeddings of  in  .
Since  is an algebraic integer, so are its conjugates  , and hence so is the product of its conjugates  . But clearly  is fixed by all of  , so it is in  ; since the only rational algebraic integers are the usual integers  , we have  .
I do not understand b), so I can't really do c) unless I try another path. What is the house of an algebraic number? | 
October 27th, 2009, 12:52 AM
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| | house hello 
thank you for your reply!
the house of  is defined to be  . | 
October 27th, 2009, 05:00 AM
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| | Quote:
Originally Posted by zverik136 hello 
thank you for your reply!
the house of  is defined to be  . |
I'm afraid we still don't know what is
Tonio | 
October 27th, 2009, 05:51 AM
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| | den The only definition of den i was given was as above:
The denominator of  , denoted by  , is the smallest positive integer  such that  is an algebraic integer.
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