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  #1  
Old October 26th, 2009, 12:56 AM
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Default conjugates of algebraic numbers

hello,
i am having a problem with the following question:

Let $\alpha \in \mathbb{C}$ be an algebraic number of degree $d$ and denote by $\alpha^{(1)}, \ldots, \alpha^{(d)}$ the conjugates of $\alpha$.

a. Let $m = den(\alpha)$, ie the smallest positive integer $m \in \mathbb{Z}$ such that $m\alpha$ is an algebraic integer. Prove that $m^d \alpha^{(1)} \ldots \alpha^{(d)} \in \mathbb{Z}$.

b. Suppose that $\alpha \neq 0$. Prove that $|\alpha| \geq den(\alpha)^{-d} |\bar{\alpha}|^{1-d}$, where $\bar{\alpha}$ is the house of $\alpha$.

c. Using b. give a proof of the following inequality of Liouville (1844): Let $\alpha$ be an algebraic number in $\mathbb{R}$ of degree $d /geq 2$. Then there is a constant $c(\alpha) > 0$ such that $ |\alpha - p/q| \geq c(\alpha) q^{-d}$ for all $p, q \in \mathbb{Z}$ with $q>0$.

I thought I would write out the whole thing for clarity

Thank you

Last edited by zverik136; October 26th, 2009 at 12:56 AM. Reason: latex rendering?
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  #2  
Old October 26th, 2009, 03:56 AM
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Originally Posted by zverik136 View Post
hello,
i am having a problem with the following question:

Let \alpha \in \mathbb{C} be an algebraic number of degree d and denote by \alpha^{(1)}, \ldots, \alpha^{(d)} the conjugates of \alpha.

a. Let m = den(\alpha), ie the smallest positive integer m \in \mathbb{Z} such that m\alpha is an algebraic integer. Prove that m^d \alpha^{(1)} \ldots \alpha^{(d)} \in \mathbb{Z}.

b. Suppose that \alpha \neq 0. Prove that |\alpha| \geq den(\alpha)^{-d} |\bar{\alpha}|^{1-d}, where \bar{\alpha} is the house of \alpha.

c. Using b. give a proof of the following inequality of Liouville (1844): Let \alpha be an algebraic number in \mathbb{R} of degree d /geq 2. Then there is a constant c(\alpha) > 0 such that |\alpha - p/q| \geq c(\alpha) q^{-d} for all p, q \in \mathbb{Z} with q>0.

I thought I would write out the whole thing for clarity

Thank you
Hi there. I tried to correct your LaTex text as much as I could since in this site, unfortunately, to write properly in LaTex we have to open sentences with [math] and close them with [/math], instead of the well known and simpler $.
Nevertheless, as you can see, somethings still didn't come out nicely, as that thing "den(\alpha)" and "d /geg2"

Tonio
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Old October 26th, 2009, 07:19 PM
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Originally Posted by zverik136
hello,
i am having a problem with the following question:

Let be an algebraic number of degree d and denote by the conjugates of .

a. Let , ie the smallest positive integer such that is an algebraic integer. Prove that .

b. Suppose that . Prove that , where is the house of .

c. Using b. give a proof of the following inequality of Liouville (1844): Let be an algebraic number in of degree . Then there is a constant such that for all with .

I thought I would write out the whole thing for clarity

Thank you
Hello zverik!

Let \sigma_1,\hdots, \sigma_d be the embeddings of \mathbb{Q}(\alpha) in \mathbb{C}.

Since m\alpha is an algebraic integer, so are its conjugates m\alpha^{(1)},\hdots,m\alpha^{(d)}, and hence so is the product of its conjugates P=m^d\alpha^{(1)}\hdots\alpha^{(d)}. But clearly P is fixed by all of \sigma_1,\hdots,\sigma_d, so it is in \mathbb{Q}; since the only rational algebraic integers are the usual integers \mathbb{Z}, we have P\in \mathbb{Z}.

I do not understand b), so I can't really do c) unless I try another path. What is the house of an algebraic number?
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Old October 27th, 2009, 12:52 AM
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Default house

hello
thank you for your reply!

the house of \alpha is defined to be \bar{\alpha} = \max (|\alpha^{(1)}|, \ldots , |\alpha^{(d)}|).
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Old October 27th, 2009, 05:00 AM
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hello
thank you for your reply!

the house of \alpha is defined to be \bar{\alpha} = \max (|\alpha^{(1)}|, \ldots , |\alpha^{(d)}|).

I'm afraid we still don't know what is den(\alpha)

Tonio
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Old October 27th, 2009, 05:51 AM
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Default den

The only definition of den i was given was as above:

The denominator of \alpha, denoted by den(\alpha), is the smallest positive integer m \in \mathbb{Z} such that m\alpha is an algebraic integer.

thank you
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