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Old November 5th, 2009, 06:00 AM
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Default Fibonacci Proof

Hi all

Prove that every 4th Fibonacci number is divisible by 3, that is 3|f4n, for all n>=1.
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Old November 5th, 2009, 06:43 AM
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Quote:
Originally Posted by sirellwood View Post
Hi all

Prove that every 4th Fibonacci number is divisible by 3, that is 3|f4n, for all n>=1.

Induction and some patience:F_{4n}=F_{4n-1}+F_{4n-2}=F_{4n-2}+F_{4n-3}+F_{4n-3}+F_{4n-4} = F_{4n-3}+F_{4n-4}+F_{4n-3}+F_{4n-3}+F_{4n-4}=...

Tonio

Pd. The solution's already present in the rightmost expression above.
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Old November 5th, 2009, 09:08 AM
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Sorry, im not sure where you are going with this one?
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