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Old December 9th, 2008, 01:07 PM
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Default absolutely continuous functions and measurable sets

I have a homework question that I need a hint on...

Given f:R->R is absolutely continuous, I have shown that f maps sets of measure zero to sets of measure zero. I am yet to show that f maps measurable sets to measurable sets. I know that E is measurable iff it differs from a g-delta or an f-sigma by a set of measure zero, and it seems like that would be the way to go. In the previous problem I was able to use the fact that absolutely continuous functions are uniformly continuous, but I don't see how that applies here. I would appreciate any help anyone could provide. Thanks.

rogerpodger

P.S. I have to turn this in today, so if anyone is able, I would really appreciate their assistance. Thanks.

Last edited by rogerpodger; December 10th, 2008 at 03:07 PM. Reason: Due Date Pending
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