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Old December 2nd, 2008, 12:39 PM
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Default Compound Interest

I am having trouble coming up with the number for n :

Lisa will invest some money on July 3, her sixteenth birthday, at 4.5% per year, compunded monthly. How much should she invest if she wants to have $ 10,000 on the November 3 following her eighteenth birthday?

I have found

P= 10,000
i= 0.045/12= 0.00375
n= ? ( not sure how to get this)

Thank you for the help
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Old December 2nd, 2008, 01:44 PM
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This formula should do the trick..

P = \frac{A}{\left(1 + \frac{r}{n}\right)^{nt}}

where P is the amount she should invest, A=10000, r is the rate, n is the number of times the interest is compounded per year, and t is number of years, here 24+4/12..
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