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Old September 12th, 2009, 07:52 AM
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Default Finding Point B Coordinates from Midpoint and Point A

I have coordinate for point A and mid-point M. I want to find an unknown coordinate B from those two points. How to do that?

I know I can do it manually cause it's a line segment but there must be a formula for making it simpler and quicker.
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Old September 12th, 2009, 08:06 AM
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Originally Posted by isharis View Post
I have coordinate for point A and mid-point M. I want to find an unknown coordinate B from those two points. How to do that?

I know I can do it manually cause it's a line segment but there must be a formula for making it simpler and quicker.
M=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)

This is the midpoint formula. Note that you have

\left(\frac{x_1+?}{2},\frac{y_1+?}{2}\right)

So, all you have to do is insert the info where it must go like this

Let's say that A=(1,3) and M=(2,4)

Then to find the x value of the point B...

\underbrace{\frac{1+?}{2}}_{\text{formula for midpoint}}=\overbrace{2}^{midpoint}

Do you see?
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Old September 12th, 2009, 08:13 AM
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I have coordinate for point A and mid-point M. I want to find an unknown coordinate B from those two points. How to do that?
If M:(c,d) is the midpoint between A:(p,q)~\&~B:(x,y) then x=2c-p~\&~y=2d-q.

Last edited by Plato; September 12th, 2009 at 08:23 AM.
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Old September 12th, 2009, 08:15 AM
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If M:(c,d)...
I did lose some generality there, huh?

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Old September 12th, 2009, 08:16 AM
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Thanks for the help, guys.
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Old September 12th, 2009, 08:20 AM
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If M:(c,d) is the midpoint between A:(p,q)~\&~B:(x,y) then x=2c-p~\&~y=2q-d.
y should be ~y=2d-q
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Old September 12th, 2009, 08:23 AM
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y should be ~y=2d-q
Yes. Thanks for the correction.
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