Math Help Forum

Math Help Forum Feed Site Feed

Go Back   Math Help Forum > Pre-University Math Help > Pre-Algebra and Algebra
Closed Thread
 
Thread Tools Display Modes
  #1  
Old October 25th, 2009, 04:32 AM
Member
 
Join Date: Dec 2008
Posts: 97
Country:
Thanks: 1
Thanked 0 Times in 0 Posts
zorro is on a distinguished road
Red face Find the value of 2 terms in the simultaneous equation

Question : For what values of \lambda and \mu , the simultaneous equations

x + y + z = 6
x + 2y + 3z = 10
x + 2y + \lambdaz = \mu
Advertisement
 
  #2  
Old October 25th, 2009, 04:46 AM
Super Member
 
Join Date: Dec 2008
Location: Scotland
Posts: 863
Country:
Thanks: 6
Thanked 341 Times in 319 Posts
Mush is a jewel in the roughMush is a jewel in the roughMush is a jewel in the roughMush is a jewel in the rough
Default

Quote:
Originally Posted by zorro View Post
Question : For what values of \lambda and \mu , the simultaneous equations

x + y + z = 6
x + 2y + 3z = 10
x + 2y + \lambdaz = \mu

Note that the first two terms of the last two equations are identical. We can rewrite these equations as:

x + 2y = 10 - 3z

x + 2y = \mu - \lambda z

So we can conclude that 10 - 3z =  \mu  -\lambda z.

You can solve for lambda and mu by comparing coefficients of z^1 \, \, \text{and} z^0 on each side of this equation.
  #3  
Old October 31st, 2009, 11:56 PM
Member
 
Join Date: Dec 2008
Posts: 97
Country:
Thanks: 1
Thanked 0 Times in 0 Posts
zorro is on a distinguished road
Default Please elaborate on ur solution

Quote:
Originally Posted by Mush View Post
Note that the first two terms of the last two equations are identical. We can rewrite these equations as:

x + 2y = 10 - 3z

x + 2y = \mu - \lambda z

So we can conclude that 10 - 3z =  \mu  -\lambda z.

You can solve for lambda and mu by comparing coefficients of z^1 \, \, \text{and} z^0 on each side of this equation.

Thanks for ur reply
But may i know what do u mean by z^0 and z^1 in the equation
  #4  
Old November 1st, 2009, 12:29 AM
Junior Member
 
Join Date: Oct 2009
Posts: 65
Country:
Thanks: 11
Thanked 7 Times in 7 Posts
harbottle is on a distinguished road
Default

z^1=z;\quad z^0=1
  #5  
Old November 1st, 2009, 01:44 AM
Member
 
Join Date: Dec 2008
Posts: 97
Country:
Thanks: 1
Thanked 0 Times in 0 Posts
zorro is on a distinguished road
Red face I am still unable to understand

Quote:
Originally Posted by harbottle View Post
z^1=z;\quad z^0=1

But how did u get z^0 = 1 z^1 = z
Could u please elaborate on that

Last edited by zorro; November 1st, 2009 at 02:01 AM.
  #6  
Old November 1st, 2009, 01:50 AM
mr fantastic's Avatar
Flow Master

 
Join Date: Dec 2007
Location: Zeitgeist
Posts: 12,235
Country:
Thanks: 2,574
Thanked 4,757 Times in 4,190 Posts
mr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond repute
Default

Quote:
Originally Posted by zorro View Post
But how did u get z^0z^1
Could u please elaborate on that
Forget the z^0z^1 business.

If 10 - 3z = \mu -\lambda z for all values of z then it should be quite plain that you need to equate the constant term on each side of the equation and you need to equate the coefficient of z on each side of the equation.
__________________
There are two things you should never try to prove: the impossible and the obvious.

The greater danger for most of us lies not in setting our aim too high and falling short; but in setting our aim too low and achieving our mark. (Michelangelo Buonarroti)

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.
  #7  
Old November 1st, 2009, 02:09 AM
Member
 
Join Date: Dec 2008
Posts: 97
Country:
Thanks: 1
Thanked 0 Times in 0 Posts
zorro is on a distinguished road
Default

Quote:
Originally Posted by mr fantastic View Post
Forget the z^0z^1 business.

If 10 - 3z = \mu -\lambda z for all values of z then it should be quite plain that you need to equate the constant term on each side of the equation and you need to equate the coefficient of z on each side of the equation.


what do u mean by equating the constant on each side of the equation?
Please could u show me the steps
  #8  
Old November 1st, 2009, 03:40 AM
mr fantastic's Avatar
Flow Master

 
Join Date: Dec 2007
Location: Zeitgeist
Posts: 12,235
Country:
Thanks: 2,574
Thanked 4,757 Times in 4,190 Posts
mr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond repute
Default

Quote:
Originally Posted by zorro View Post
what do u mean by equating the constant on each side of the equation?
Please could u show me the steps
I will not.

Are you honestly saying that you do not know what the constant term is in 10 - 3z and \mu - \lambda z? If that's the case then sorry but there's nothing educational to be gained by someone writing a solution for you to simply copy.

The cold hard fact (based on this thead and others) is that you need to go back and thoroughly revise basic material (such as polynomials) because the questions you are asking (and no doubt other questions you have yet to meet or ask) assume you are competent with that material.

Then read threads like this one again.
__________________
There are two things you should never try to prove: the impossible and the obvious.

The greater danger for most of us lies not in setting our aim too high and falling short; but in setting our aim too low and achieving our mark. (Michelangelo Buonarroti)

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.
  #9  
Old November 1st, 2009, 03:46 AM
Member
 
Join Date: Dec 2008
Posts: 97
Country:
Thanks: 1
Thanked 0 Times in 0 Posts
zorro is on a distinguished road
Default

Quote:
Originally Posted by mr fantastic View Post
I will not.

Are you honestly saying that you do not know what the constant term is in 10 - 3z and \mu - \lambda z? If that's the case then sorry but there's nothing educational to be gained by someone writing a solution for you to simply copy.

The cold hard fact (based on this thead and others) is that you need to go back and thoroughly revise basic material (such as polynomials) because the questions you are asking (and no doubt other questions you have yet to meet or ask) assume you are competent with that material.

Then read threads like this one again.

You didnt understand my question . I need to know what to put in the values of mu and lambda
  #10  
Old November 1st, 2009, 03:50 AM
mr fantastic's Avatar
Flow Master

 
Join Date: Dec 2007
Location: Zeitgeist
Posts: 12,235
Country:
Thanks: 2,574
Thanked 4,757 Times in 4,190 Posts
mr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond repute
Default

Quote:
Originally Posted by zorro View Post
You didnt understand my question . I need to know what to put in the values of mu and lambda
You have been told how to get the values of \mu and \lambda. Review my replies and then show your work if you still need help.
__________________
There are two things you should never try to prove: the impossible and the obvious.

The greater danger for most of us lies not in setting our aim too high and falling short; but in setting our aim too low and achieving our mark. (Michelangelo Buonarroti)

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.
  #11  
Old November 1st, 2009, 04:08 AM
Member
 
Join Date: Dec 2008
Posts: 97
Country:
Thanks: 1
Thanked 0 Times in 0 Posts
zorro is on a distinguished road
Default

Quote:
Originally Posted by mr fantastic View Post
Forget the z^0z^1 business.

If 10 - 3z = \mu -\lambda z for all values of z then it should be quite plain that you need to equate the constant term on each side of the equation and you need to equate the coefficient of z on each side of the equation.


In this u have quoted to equate the coefficient of z on each side of the equation
and here the coefficient of z would be 3 and lambda ...is that correct
If correct then which equation should this coefficient should be equated
  #12  
Old November 1st, 2009, 04:14 AM
mr fantastic's Avatar
Flow Master

 
Join Date: Dec 2007
Location: Zeitgeist
Posts: 12,235
Country:
Thanks: 2,574
Thanked 4,757 Times in 4,190 Posts
mr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond repute
Default

Quote:
Originally Posted by zorro View Post
In this u have quoted to equate the coefficient of z on each side of the equation
and here the coefficient of z would be 3 and lambda ...is that correct
If correct then which equation should this coefficient should be equated
On the left hand side the coefficient of z is -3. On the right hand side the coefficient of z is -\lambda. So -3 = -\lambda \Rightarrow \lambda = 3.

Your job is to use similar reasoning with the constant terms.
__________________
There are two things you should never try to prove: the impossible and the obvious.

The greater danger for most of us lies not in setting our aim too high and falling short; but in setting our aim too low and achieving our mark. (Michelangelo Buonarroti)

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.
  #13  
Old November 1st, 2009, 04:40 AM
Member
 
Join Date: Dec 2008
Posts: 97
Country:
Thanks: 1
Thanked 0 Times in 0 Posts
zorro is on a distinguished road
Default

Quote:
Originally Posted by mr fantastic View Post
On the left hand side the coefficient of z is -3. On the right hand side the coefficient of z is -\lambda. So -3 = -\lambda \Rightarrow \lambda = 3.

Your job is to use similar reasoning with the constant terms.

So the value of lambda = 3 and mu = 10

is that correct ,then what is the use of the other equations in the question ?
  #14  
Old November 1st, 2009, 05:19 AM
Raoh's Avatar
Member
 
Join Date: Jun 2009
Location: Somewhere between the ocean and a sea..
Posts: 217
Thanks: 81
Thanked 48 Times in 46 Posts
Raoh will become famous soon enough
Send a message via MSN to Raoh
Smile

yes,it is correct ,\lambda =3,\mu =10.
__________________
"Everything starts somewhere although many physicists disagree"
  #15  
Old November 1st, 2009, 05:40 AM
mr fantastic's Avatar
Flow Master

 
Join Date: Dec 2007
Location: Zeitgeist
Posts: 12,235
Country:
Thanks: 2,574
Thanked 4,757 Times in 4,190 Posts
mr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond reputemr fantastic has a reputation beyond repute
Default

Quote:
Originally Posted by Raoh View Post
yes,it is correct ,\lambda =3,\mu =10.
These are the values for the system to have infinite solutions. But having reviewed the original post, I find that that the OP hasn't said what's meant to be happening with the system ....

Quote:
Originally Posted by zorro View Post
Question : For what values of \lambda and \mu , the simultaneous equations

x + y + z = 6
x + 2y + 3z = 10
x + 2y + \lambdaz = \mu
This question is incomplete. What is meant to happen with these equations? Do you want:

Infinite solutions? Unique solution? No solution?
__________________
There are two things you should never try to prove: the impossible and the obvious.

The greater danger for most of us lies not in setting our aim too high and falling short; but in setting our aim too low and achieving our mark. (Michelangelo Buonarroti)

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.

  • To view links or images in signatures your post count must be 10 or greater. You currently have 0 posts.
The following users thank mr fantastic for this useful post:
Donate to MHF
Closed Thread

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off
Forum Jump


All times are GMT -7. The time now is 03:21 AM.


Powered by vBulletin® Version 3.7.3
Copyright ©2000 - 2009, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.2.0 ©2008, Crawlability, Inc.
©2005 - 2009 Math Help Forum


Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.