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  #1  
Old November 2nd, 2009, 12:07 PM
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Default equation of a graph

Bruce is given the graph of y = 3x - 2

He is going to draw a second graph on the same axes.

He wants the x-coordinates of the points of intersection of the two graphs to be the solutions to the quadratic equation x^2 + x - 7 = 0

Work out the equation of the graph that needs to be drawn. Do not draw the graph.


I have tried a few ways of doing this -not sure if I am right!

Firstly:

x^2 + x -7 = 3x - 2 and solved, but soon realised that this gave me the x-cocordinates but not the 'equation of the graph that needs to be drawn'.

Secondly:

adding the two equations and trying to solve as a pair of simultaneous equations -didn't get very far that way either.

I'm a bit stumped, I'm not sure how I would go about tackling this kind of problem -help!
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Old November 2nd, 2009, 05:17 PM
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Originally Posted by GAdams View Post
Bruce is given the graph of y = 3x - 2

He is going to draw a second graph on the same axes.

He wants the x-coordinates of the points of intersection of the two graphs to be the solutions to the quadratic equation x^2 + x - 7 = 0

Work out the equation of the graph that needs to be drawn. Do not draw the graph.

I have tried a few ways of doing this -not sure if I am right!

Firstly:

x^2 + x -7 = 3x - 2 and solved, but soon realised that this gave me the x-cocordinates but not the 'equation of the graph that needs to be drawn'.

Secondly:

adding the two equations and trying to solve as a pair of simultaneous equations -didn't get very far that way either.

I'm a bit stumped, I'm not sure how I would go about tackling this kind of problem -help!
Let the required graph have the equation y = ax^2 + bx + c. The intersection of this graph with y = 3x - 2 is found by solving ax^2 + bx + c = 3x - 2. Re-arrange this so that you can compare it with x^2 + x - 7 = 0. Hence get the values of a, b and c.
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Old November 3rd, 2009, 11:18 AM
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Originally Posted by mr fantastic View Post
Let the required graph have the equation y = ax^2 + bx + c. The intersection of this graph with y = 3x - 2 is found by solving ax^2 + bx + c = 3x - 2. Re-arrange this so that you can compare it with x^2 + x - 7 = 0. Hence get the values of a, b and c.
I'm not sure what you mean by 're-arrange this' , is it this?:

ax^2 + bx - 3x + c + 2 = 0 ?

I can't see how this would work.
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Old November 3rd, 2009, 11:58 AM
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ooh, ooh, I think I got it....

Is it:

x^2 + 4x - 5 ??
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Old November 3rd, 2009, 11:46 PM
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ooh, ooh, I think I got it....

Is it:

x^2 + 4x - 5 ??
I get c = -9 ....
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