Math Help Forum

Math Help Forum Feed Site Feed

Go Back   Math Help Forum > Pre-University Math Help > Pre-Algebra and Algebra
Reply
 
Thread Tools Display Modes
  #1  
Old November 6th, 2009, 02:24 AM
rowe's Avatar
Junior Member
 
Join Date: Jul 2009
Posts: 38
Country:
Thanks: 7
Thanked 11 Times in 11 Posts
rowe is on a distinguished road
Default Rules of logarithms

Solve for x:

3x - 2 = e^x

ln(3x-2) = x

At this point, I'm wondering if there's any rule I can apply to ln(3x-2) to get the x term out.
Reply With Quote
Advertisement
 
  #2  
Old November 6th, 2009, 03:54 AM
Member
 
Join Date: Oct 2009
Location: Brisbane
Posts: 112
Country:
Thanks: 2
Thanked 42 Times in 41 Posts
Debsta will become famous soon enough
Default

Do you have to solve it algebraically?
If not, you could draw the graph of y = 3x-2 and y = e^x on a GC and find the x-coordinate of where they intersect.
Reply With Quote
  #3  
Old November 6th, 2009, 03:57 AM
Bacterius's Avatar
Member
 
Join Date: Nov 2009
Location: Albany
Posts: 145
Country:
Thanks: 3
Thanked 28 Times in 26 Posts
Bacterius is on a distinguished road
Send a message via MSN to Bacterius
Default Reply

Solving a logarithmic equation graphically seems a bit of a laugh since the values are highly irrationnal. I can't find a way to solve your equation though ... well its late.
Reply With Quote
  #4  
Old November 6th, 2009, 04:06 AM
rowe's Avatar
Junior Member
 
Join Date: Jul 2009
Posts: 38
Country:
Thanks: 7
Thanked 11 Times in 11 Posts
rowe is on a distinguished road
Default

"Highly irrational"? I thought there was only one kind, hehe!

Yeah, I'd like an algebraic solution to this. Graphs are for engineers
Reply With Quote
  #5  
Old November 6th, 2009, 04:16 AM
Senior Member
 
Join Date: Aug 2009
Location: Israel
Posts: 388
Country:
Thanks: 32
Thanked 140 Times in 129 Posts
Defunkt has a spectacular aura aboutDefunkt has a spectacular aura about
Default

Quote:
Originally Posted by rowe View Post
"Highly irrational"? I thought there was only one kind, hehe!

Yeah, I'd like an algebraic solution to this. Graphs are for engineers
According to WolframAlpha, this is solved using the Lambert W function.

Are you sure this was the equation you wanted to solve?
Reply With Quote
The following users thank Defunkt for this useful post:
Donate to MHF
  #6  
Old November 6th, 2009, 04:16 AM
MHF Contributor
 
Join Date: Apr 2005
Posts: 3,489
Thanks: 324
Thanked 1,213 Times in 1,114 Posts
HallsofIvy has much to be proud ofHallsofIvy has much to be proud ofHallsofIvy has much to be proud ofHallsofIvy has much to be proud ofHallsofIvy has much to be proud ofHallsofIvy has much to be proud ofHallsofIvy has much to be proud ofHallsofIvy has much to be proud ofHallsofIvy has much to be proud of
Default

Well, there is no "algebraic solution" for this nor, in general, for equations in which the "unknown" appear both inside and outside of a transcendental function. You might be able to write the solution in terms of the Lambert W function (which is defined as the inverse function to f(x)= xe^x but I don't see how offhand.
Reply With Quote
The following users thank HallsofIvy for this useful post:
Donate to MHF
  #7  
Old November 6th, 2009, 04:50 AM
rowe's Avatar
Junior Member
 
Join Date: Jul 2009
Posts: 38
Country:
Thanks: 7
Thanked 11 Times in 11 Posts
rowe is on a distinguished road
Default

Thanks guys, there must be a mistake with the problem.
Reply With Quote
Reply

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off
Forum Jump


All times are GMT -7. The time now is 08:12 AM.


Powered by vBulletin® Version 3.7.3
Copyright ©2000 - 2009, Jelsoft Enterprises Ltd.
SEO by vBSEO 3.2.0 ©2008, Crawlability, Inc.
©2005 - 2009 Math Help Forum


Math Help Forum is a community of maths forums with an emphasis on maths help in all levels of mathematics.
Register to post your math questions or just hang out and try some of our math games or visit the arcade.