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#1

$Old$ November 10th, 2009, 05:53 AM

hooke $hooke is offline$

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Find the Cartesian equation of each of the curves with the following parametric equations .

$x=t^2+t$ , $y=t^2-t$ -- 1

$t^2=x-t$ , $t^2=y+t$

$x-t=y+t$

$t=\frac{x-y}{2}$ --- 2

Put 2 into 1

$y=(\frac{x-y}{2})^2-\frac{x-y}{2}$

$x^2+y^2-2xy-2x-2y=0$

Am i correct or there is a shorter approach ?

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#2

$Old$ November 10th, 2009, 06:09 AM

adkinsjr $adkinsjr is offline$

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Originally Posted by hooke $View Post$

Find the Cartesian equation of each of the curves with the following parametric equations .

$x=t^2+t$ , $y=t^2-t$ -- 1

$t^2=x-t$ , $t^2=y+t$

$x-t=y+t$

$t=\frac{x-y}{2}$ --- 2

Put 2 into 1

$y=(\frac{x-y}{2})^2-\frac{x-y}{2}$

$x^2+y^2-2xy-2x-2y=0$

Am i correct or there is a shorter approach ?

I don't see a shorter approach, but you're approach looks like it worked.

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