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Old November 16th, 2009, 08:33 PM
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Default System of equations

Could someone point me in the right direction? I've been wrestling with this one for a while.

100x + 200y + 500z = 47
350x + 5y + 250z = 33.9
200x + 80y + 100z = 23.4
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Old November 16th, 2009, 08:59 PM
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Quote:
Originally Posted by absvalue View Post
Could someone point me in the right direction? I've been wrestling with this one for a while.

100x + 200y + 500z = 47
350x + 5y + 250z = 33.9
200x + 80y + 100z = 23.4
multiply the 2nd equation by -2 and get

-700x -10y -500z = -67.80

Now cancel out the z in the 1st and new equation we got

-600x +190y = -20.80

Now multiply equation 2 by 2 and multiply equation 3 by -5 to create 2 new equations.

Now add the two new equations and the z's should cancel out leaving

-300x -390y = -49.20

Can you finish up from here?
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Old November 16th, 2009, 09:14 PM
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Hello, absvalue!

It can be done with basic algebra IF we're careful . . .


Quote:
\begin{array}{cccc}100x + 200y + 500z &=& 47 & [1] \\
350x + 5y + 250z &=& 33.9& [2] \\
200x + 80y + 100z &=&  23.4 & [3] \end{array}
\begin{array}{cccccc}\text{Multiply }2 \times [2]\!: & 700x + 10y + 500z &=&67.8 \\
\text{Subtract [1]:} & \text{-}100x - 200y - 500z &=& \text{-}47 \end{array}

We have: .600x - 190y \:=\:20.8 \;\;[4]


\begin{array}{cccccc}
\text{Multiply }5 \times [3]\!: &1000x + 400y + 500z &=& 117 \\
\text{Subtract [1]:} & \text{-}100x - 200y - 500z &=& \text{-}47 \end{array}

We have: .900x + 200y \:=\:70\;\;[5]


\begin{array}{ccccc}
\text{Multiply }2 \times [5]\!: & 1800x + 400y &=& 140 \\
\text{Multiply }3\times[4]\!: & 1800x - 570y &=& 62.4 \end{array}

Subtract: . 970y \:=\:77.6 \quad\Rightarrow\quad \boxed{y \:=\:0.08}


Substitute into [5]: .900x + 200(0.08) \:=\:70 \quad\Rightarrow\quad \boxed{x \:=\:0.06}

Substitute into [3]: .200(0.06) + 80(0.08) + 100z \:=\:23.4 \quad\Rightarrow\quad \boxed{z \:=\:0.05}

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Old November 17th, 2009, 08:04 AM
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Thanks, that makes sense now. You guys are awesome.
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