Adding a monster of a rational expression

Charchar · #1 $Old$ November 19th, 2009, 08:25 PM

I am having a hard time with this, I am not sure if its just the sheer size or something in my calculations. I am grateful to anyone who wants to take this on:

4a^2-20a/a^2+2a-35 + 3a-6/3a^2-10a+8

So far all I have is the simplified version of the two denominators
(a+7)(a-5) (3a-4)(a-2)

Then after this the equation is too huge for me to deal, with it seems.

Amer · #2 $Old$ November 19th, 2009, 09:09 PM

Quote:

Originally Posted by Charchar $View Post$

I am having a hard time with this, I am not sure if its just the sheer size or something in my calculations. I am grateful to anyone who wants to take this on:

4a^2-20a/a^2+2a-35 + 3a-6/3a^2-10a+8

So far all I have is the simplified version of the two denominators
(a+7)(a-5) (3a-4)(a-2)

Then after this the equation is too huge for me to deal, with it seems.

$\frac{4a^2 -20a}{a^2+2a-35} + \frac{3a-6}{3a^2-10a+8}$

$\frac{4a(a-5)}{(a+7)(a-5) } + \frac{3(a-2)}{(3a-4)(a-2)}$

$\frac{4a}{a+7} + \frac{3}{(3a-4)}$

it is simple now, is all things clear

Charchar · #3 $Old$ November 19th, 2009, 09:40 PM

ahhh, I see clearly now. Thank you very much for your help!